Latest ITC Aptitude Question SOLUTION: Q. One rectangle having shorter side is 2m and is fold along the line joining the midpoint of the longer side. the ratio of longer and shorter side in both new and old rectangle re

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Q. One rectangle having shorter side is 2m and is fold along the line joining the midpoint of the longer side. the ratio of longer and shorter side in both new and old rectangle remains same than what was the length of longer side in new rectangle.

Option
a) v2
b) 2v2
c) 2
d) None of these

Asked In ITC (12 years ago)

Solved Rameez Akhtar Read Solution (5)

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Read Solution (5) :

Rameez Akhtar  (12 years ago)

let sides be x and y
smaller side=x
longer side=y

now as y is folded in half, then side y becomes y/2
now one side is x other is y/2
ratio of sides is either x/(y/2) or (y/2)/x

comparing

initial ratio= x/y
final ratio= x/(y/2) or (y/2)/x

x/y=x/(y/2) is not possible

so, x/y=(y/2)/x is possible

as x=2
2/y=(y/2)/2
by solving we get y=2v2

Is this solution Helpfull? Yes (17) | No (7)  

RIMI  (12 years ago)

2
the length of longer side at older l
then ratio=l:2
if l/2 is longer then shorter will be (l/2)/shorter=l/2 it is not possible because the shorter value must be 2 .
so the longer value is 2

Is this solution Helpfull? Yes (4) | No (5)  

srivalli kadali  (11 years ago)

'a' is length of longer side
a/2=2/a/2
a^2=8
a=2*v2
sides of new rectangle is v2 and 2
length of the longer side is 2
ans : option C

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Mallikarjuna M  (9 years ago)

answer is 2v2

Is this solution Helpfull? Yes | No (1)  

vardhan reddy  (8 years ago)

l/2 =2/(l/2)
so l/2=4/l
and l^2=8
l=2^(3/2)
answer is option b

Is this solution Helpfull? Yes | No (1)  

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