Latest Others Aptitude Question SOLUTION: A alone can complete a work in 16 days and B alone in 12 days.starting with A,they work on alternate days the total work completed in??????

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(#M40001498) OTHERS HR Interview question time and work Keep an EYE

A alone can complete a work in 16 days and B alone in 12 days.starting with A,they work on alternate days the total work completed in??????

Asked In Others jayalakshmi (13 years ago)

Solved Tijo Jose Read Solution (7)

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vamsi krishna reddy  (13 years ago)

(A+B)’s 2 days work = 1/16 + 1/12 = 7/48
work done in 6 pairs of days = (7/48) * 6 = 7/8
remaining work = 1- 7/8 = 1/8
work done by A on 13th day = 1/16
remaining work = 1/8 – 1/16 = 1/16
on 14th day, it is B’s turn
1/12 work is done by B in 1 day.
1/16 work is done by B in ¾ day.
Total time taken = 13 ¾ days.

Is this solution Helpfull? Yes (13) | No (6)  

suneelkumar.avvari  (13 years ago)

work done by the 'A'in one day = 1/16
work done by the 'B'in one day = 1/12
work done by the both in 2 days = (1/16)+(1/12) = 7/48
no of pairs of days required to complete the work = 48/7 = 6.86
so total required no of days = 6.86*2 = 13.72 = 13 3/4 days

Is this solution Helpfull? Yes (10) | No (9)  

Tijo Jose  (13 years ago)

work done by the 'A'in one day = 1/16 = 3/48
work done by the 'B'in one day = 1/12 = 4/48
(48 = lcm(12, 16))
Assuming the work divided into 48 parts, the amount of work completed each day forms the series 3, 4, 3, 4, 3, 4, ...
In 12 days, 42 parts will be finished
In 13 days, 45 parts will be finished
In 14 days, 49 parts will be finished
But since there is only 48 parts of the work, the work will be finished in 13.75 days. Since number of days should be integer, it means answer is 14 days.

Is this solution Helpfull? Yes (5) | No (5)  

Isha Tyagi  (13 years ago)

A's 1 day work=1/16
B's 1 day work=1/12
(A+B)'s 1 day work=1/16+1/12=7/48
(A+B)'s=48/7
Since they work on alternative days therefore=(48/7)*2=13.72

Is this solution Helpfull? Yes (2) | No (5)  

Gnanavinay Murarisetty  (7 years ago)

A will complete work in 16 days where as B will complete the work in 12 days.
Total Work =LCM of (16,12)=48
Work done by A per day =48/16=3/day
Work done by B per day =48/12=4/day
A+B)/2days=7
for 12 days They will complete 42 parts
And again 13th day A will complete 3
so total 45 is completed
Reamining is 3
B has a capability of doing 4 parts per day so,it took 3/4 th of the day
total 13 3/4 days to complete the work

Is this solution Helpfull? Yes (1) | No   

RAM  (13 years ago)

A's one day work->1/16
B's one day work->1/12

(A+B)'s one day work= 1/16+1/12= 7/48
(A+B)'s 6 days work=42/48
After 6 days 1/8 work will be left
1/8 work will be done in->
1 part of work is done in 48/7 days
1/8 work will be done in 48/7 * 1/8=6/7
Total time -> 6 + 6/7
=48/7 days

Is this solution Helpfull? Yes | No (5)  

niv  (4 years ago)

a=16 days
b=12days
lcm =48
a's one day work =48/16=3
b's one day work=48/12=4
a+b one day work=7x6=42
remaining work=48-42=6
total days=(6x2)+1+3/4=13 3/4

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