Latest Elitmus Aptitude Question SOLUTION: A die is rolled twice. What is the probability of getting a sum equal to 9? Options A. 2/3 B. 2/9 C. 1/3 D. 1/9

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(#M40102227) ELITMUS Numerical Ability question Keep an EYE

A die is rolled twice. What is the probability of getting a sum equal to 9?

Options
A. 2/3
B. 2/9
C. 1/3
D. 1/9

Asked In Elitmus Diya (9 years ago)

Unsolved Read Solution (16)

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Read Solution (16) :

Bhavya Jain  (8 years ago)

total pair 6*6 = 36
and pair whose sum is = 9 i.e= (6,3), (3,6) ,(5,4) and (4,5)
so probability of getting sum equal to 9 = 4/36= 1/9

Is this solution Helpfull? Yes (16) | No   

himanshu dadhich  (8 years ago)

1/9
ek bar ki baat h
ek batta no to phr uski foki tut gyi

Is this solution Helpfull? Yes (2) | No (1)  

goutham  (6 years ago)

Total number of outcomes possible when a die is rolled = 6 (∵ any one face out of the 6 faces)

Hence, total number of outcomes possible when a die is rolled twice, n(S) = 6 × 6 = 36

E = Getting a sum of 9 when the two dice fall = {(3, 6), {4, 5}, {5, 4}, (6, 3)}

Hence, n(E) = 4

P(E) =n(E)/n(S) =4/36=1/9

Is this solution Helpfull? Yes (1) | No   

chandan kumar  (8 years ago)

d) 1/9

no of favorable event is {(3,6),(6,3),(4,5),(5,4)}=4
no of total event =36
so probability=4/36=1/9

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SHAMSHER ALAM  (8 years ago)

d)1/9
There is four chances (3,6),(6,3),(5,4) and (4,5)
prob=4/36

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praveendas  (8 years ago)

1/9 is the ans

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Srinidhi B R  (7 years ago)

No of ways of getting the sum 9 from 2 pairs of dice is 4 times.
Total no of combinations from 2 pairs of dice is 36.
Hence the probability is 4/36 = 1/9

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Sharan Raj  (7 years ago)

Total possibilities:36
Possibilities of sum eq to 9 :4--->{(3,6),(4,5),(5,4),(6,3)}
prob=4/36=1/9

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Priyanshi Jajoo  (6 years ago)

ans= 1/9
total cases= 6*6=36
sum equal to 9= {(3,6), (6,3), (4,5), (5,4)}=4
probabillity= 4/36
=1/9

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krutika waddar  (6 years ago)

D. 1/9
sample space(3,6)(6,3)(4,5)(5,4) for two outcomes

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Divya Batra  (6 years ago)

answer is 1/9

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Balakantam kota  (6 years ago)

4/6=2/3
Because one die

Is this solution Helpfull? Yes | No (2)  

vikash  (5 years ago)

Time saving trick ---> when 2 dices are thrown and sum is ask then use this rule
if sum is upto 7 then subtract -1 into sum
if sum is greater than 7 then do 13-sum
eg In above question 13-9=4
4/36=1/9
eg
if sum is 5 then 6-1=5
5/36
this valid for only 2 dices

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kirti  (5 years ago)

4,5 and 5,4 and 6,3 and 3,6 over 36 assumptions hence 4/36

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neeraj  (4 years ago)

two die 6^2=36
sum of observation=(3,6),(6,3),(4,5),(5,4) = 4
probability = sum of observation/possibility
probability = 4/36 = 1/9

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Sarthak Kundu  (2 years ago)

4/36 = 1/9 Option D

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