Latest Capgemini Aptitude Question SOLUTION: Is n odd ? Starement I: an -bn is divisible by a - b. Statement II: an + bn is not divisible by a + b. Using 1st Statement only. Using 2nd statement only.

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Is n odd ? Starement I: an -bn is divisible by a - b. Statement II: an + bn is not divisible by a + b.
Using 1st Statement only.
Using 2nd statement only.

Asked In Capgemini Rahul kumar singh (11 years ago)

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SDeep Bhattacharya  (11 years ago)

Using only the 2nd statement we can infer that 'n' is odd.

Reason:-
In the expression (a^n + b^n),if we replace 'a' by '(-b)',then the expression becomes [(-b)^n + b^n],now this expression will be zero if and only if n be an odd +ve integer,bcoz then the expression will be {-b^n+b^n=0}.

Therefore according to the principle of vanishing method of factorisation,

(a-{-b}) =>(a+b) will be a factor of the given expression,i.e, of (a^n+b^n),when

n is an odd +ve integer..
:-):-)

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Ais  (9 years ago)

i tested like dis..hope this s right..
first we will take condition a^-n-b^n,apply n=2(even) divisible by a-b...because a^2-b^2 is (a-b) (a+b) hence divisible by a-b
nw apply n=1(odd) ,it is divisible by a-b.therefore we cannot predict by first statement..
second statement will exactly prove the condition that it is divisible only when power is odd..take n=1 or 3 for second case,it will be divisible by a+b...it will not be divisible by even..so second statement only

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