Latest self Aptitude Question SOLUTION: let y=((1+ai)/(b-i))^x,where a,b,x and y are integers.it is known that x is an even number greater than 100 but not divisible by 4,which of the following statements willl always be

• Placement Papers
• /
• self

self Question Papers:

(#M40010525) SELF question Keep an EYE

let y=((1+ai)/(b-i))^x,where a,b,x and y are integers.it is known that x is an even number greater than 100 but not divisible by 4,which of the following statements willl always be true??(i is complex such that i^2=(-1))

deepika (11 years ago)

Unsolved Read Solution (4)

Is this Puzzle helpful?   (0)   (2) Submit Your Solution

Read Solution (4) :

Jamil Ahmed  (11 years ago)

Where are the statements?

Is this solution Helpfull? Yes (1) | No   

tapesh  (8 years ago)

d.both a and b can take any values as long as they are equal.

y=((1+ai)/(b-i))^x
=(1/(i)^x)*((-i+a)/(b-i))^x ---------->eqn 1 (take i common from (1+ai)^x)
now since x=2n>100 and not equal to 4m.
so let, x=2n
then, 1/(i)^x = (1/(i^2))^n
= (-1)^n
=k (k is either +1 or -1 doesn't matter since it is integr ) (just for writing simplicity)
Now in eqn 1,
y= k*((-i+a)/(b-i))^x ------------>eqn 2
in second part of our equation 2 multiply both numerator and denominator by (b+i)
i.e.
y= k*( ((b-a)i-1-ab) / (b+1) )^x
Now, for y to be integer b-a must equal to zero.

Is this solution Helpfull? Yes (1) | No   

deepika  (11 years ago)

im sorry,
a.both a and b are positive but not equal
b.both a and b are negative and not equal
c.both a and b are prime numbers and not equal
d.both a and b can take any values as long as they are equal.

Is this solution Helpfull? Yes | No   

Rajat Sood  (8 years ago)

please help to solve this problem

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.