Latest exam Aptitude Question SOLUTION: given: {{{x=2y<(or equal to)4}}} {{{x+y<(or equal to)3}}} {{{x>(or equal to)0}}}, {{{y>(orequal to)0}}} the way to solve it is linear programming

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(#M40105891) EXAM Numerical Ability question Keep an EYE

given: {{{x=2y<(or equal to)4}}}
{{{x+y<(or equal to)3}}}
{{{x>(or equal to)0}}}, {{{y>(orequal to)0}}} the way to solve it is linear programming

Asked In exam (9 years ago)

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