Latest TCS Aptitude Question SOLUTION: the prime factorization of integer N is A*A*B*C,WHERE A,B,C are prime nos.How many factors does N have??

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the prime factorization of integer N is A*A*B*C,WHERE A,B,C are prime nos.How many factors does N have??

Asked In TCS dola (11 years ago)

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Nandhini  (11 years ago)

the prime factorization of integer n is (a^p)*(b^q)*(c^r)

so the number of factors of n will be expressed by the formula (p+1)*(q+1)*(r+1)

given the prime factorization of integer n is (a^2)*(b^1)*(c^1)
so the number of factors of n = (2+1)*(1+1)*(1+1) = 3*2*2 = 12

Is this solution Helpfull? Yes (21) | No   

PARAG KAMRA  (11 years ago)

A=1,B=2,C=3
(1+1)*2*3=12 FACTORS(ANS)

Is this solution Helpfull? Yes (18) | No (3)  

vikranth  (11 years ago)

N=A^2*B*C
no. of factors=(2+1)(1+1)(1+1)
=12

Is this solution Helpfull? Yes (9) | No (2)  

Garima  (11 years ago)

N will have 3*2*2 = 12 factors.

Is this solution Helpfull? Yes (2) | No (7)  

disha verma  (11 years ago)

nt able to understand :(

Is this solution Helpfull? Yes (1) | No   

disha verma  (11 years ago)

plz explain

Is this solution Helpfull? Yes | No (1)  

nikhil panjwani  (11 years ago)

=4!/2!
permutation with 2 no. alike

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