Latest TCS Aptitude Question SOLUTION: The letters in the word ABUSER are permuted in all possible ways and arranged in alphabetical order then find the word at position 49 in the permuted alphabetical order? a) ARBSEU

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The letters in the word ABUSER are permuted in all possible ways and arranged in alphabetical order then find the word at position 49 in the permuted alphabetical order?
a) ARBSEU
b) ARBESU
c) ARBSUE
d) ARBEUS

Asked In TCS krishnamurthy (12 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

Akash Soni  (12 years ago)

Firstly arrange it in alphabatical order i.e
ABERSU
Take first two letter as a constant i.e ABersu(remaining ersu can be arranged in 4! ways)
the next letter according to dictionary is AEbrsu take first two letter as a constant i.e AEbrsu(remaining brsu can be arranged in 4! ways)
so far we had completed 48 words the
49 word is ARBESU

Is this solution Helpfull? Yes (57) | No (2)  

nagarjun  (12 years ago)

AB**** =4!= 24 ways
AE****=4!=24 ways next word is 49th so
AR**** in alphabetical order **** will be BESU
ans is B

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Navjyot Yadav  (12 years ago)

ABUSER(ORIGINAL)
ABERSU(ALPHABETICAL)
AB(E,R,S,U) CAN BE ARRANGE AS 4!=24 WAYS
AE(B,R,S,U) CAN BE ARRANGE AS 4!=24 WAYS
"ARBESU" WOULD BE THE 49TH WORD.

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Abhishek kUNDU  (12 years ago)

plz xplain it..can't understand.

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esther  (11 years ago)

ans is:ARBESU.
At first arrange the word in alphabatical order.
know it will be ABERSU.know take the first letter of original word it is A
A-0*5!(before A there is no letter so it is 0 then put * then except A there is 5 letters)
know there is BERSU
R-2*4!(before R there is 2 letters so 2*remaining 4 letters without including A&R)
know BESU
B-0*3!
know ESU
E-0*2!
SU
S-0*1!
then the word ARBESU=1
0*5!+2*4!+0*3!+0*2!+0*1!+1=49.
the word at 49th position is ARBESU

Is this solution Helpfull? Yes (1) | No (1)  

suganya  (11 years ago)

Ans:ARBESU (b)

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Anshul jain  (9 years ago)

any explain in detail????????

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neha upadhyay  (8 years ago)

The best way to solve this problems is Just ask how many words starts with A. If we fix A, then the remaining letters can be arranged in 5! ways = 120. So the asked word must start with A.
Arrange all the given letters in alphabetical order. ABERSU
Let us find all the words start with AB. AB**** = 4!= 24 ways
Now we find all the words start wit AE. AE****= 4!= 24 ways
So next word start with AR and remaining letters are BESU

So option B

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