Latest TCS Aptitude Question SOLUTION: A father purchases dress for his three daughter. The dresses are of same color but of different size .the dress is kept in dark room .What is the probability that all the three wi

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A father purchases dress for his three daughter. The dresses are of same color but of different size .the dress is kept in dark room .What is the probability that all the three will not choose their own dress...




a) 2/3 b) 1/3 c) 1/6 d) 1/9

Asked In TCS harshit gupta (11 years ago)

Unsolved Read Solution (24)

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Read Solution (24) :

viresh  (11 years ago)

a dosesnot choose his dress 2/3
b dosesnot choose his dress 1/2
c dosesnot choose his dress 1
total 1/3

Is this solution Helpfull? Yes (109) | No (17)  

shreya gupta  (11 years ago)

let the right sequence be A B C
NOW there are 6 possibilities for the 3 choosing their dress
A B C
A C B
B A C
B C A
C A B
C B A
Here in the question its asked the probability of all the 3 not to choose there own dress that means 1 can choose her own dress
total unfavourable outcomes are
B C A AND C A B
THEREFORE
PROBABILITY = UNFAVOURABLE OUTCOMES/TOTAL POSSIBILITIES
ie 2/6 = 1/3

Is this solution Helpfull? Yes (60) | No (3)  

Raj  (11 years ago)

ans wil b 2/3..
probabilty always 1..
so getting right dresses is 1 out of three 1/3
so nt getting right will b 1-1/3= 2/3..

Is this solution Helpfull? Yes (47) | No (28)  

RAVI KIRAN  (11 years ago)

Proper Selections: A B C
A C B
C B A
B A C (ie. total 4)

Improper selection: B C A , C A B (ie. total 2)
Probability for improper selection= 2/6 = 1/3

Is this solution Helpfull? Yes (29) | No (4)  

Reema khan  (11 years ago)

let the three b A B C
the possibilities are... :
1-- > all three take the right dress or
2-- > A takes B's...B takes c's and C takes A's dress or
3-- > A takes c's...B takes A's..and C takes B's dress...
so the probabilty that all three will not choose their own dress=2/3
hence ans is a) 2/3

Is this solution Helpfull? Yes (6) | No (5)  

Akash Soni  (11 years ago)

there are only 2 cases which are favourable hence the answer is 2/6=1/3

Is this solution Helpfull? Yes (5) | No (3)  

Yash Ajmera  (11 years ago)

Ans. (b) 1/3

See there are only 3 possibilities
1. All 3 get correct Dress
2. Any 1 get correct Dress
3. No one gets correct dress.
So Probability will be 1/3 ( As for 3rd option only we will not take 2nd option
as Not all three have wrong dress in 2nd option).

We have to also ignore - 2 girls get correct dress as if so then 3rd will
automatically correct. (i.e.. 0, 1, 3) Then prob of 0 = 1/3.

Is this solution Helpfull? Yes (5) | No   

akshat sinha  (8 years ago)

correct answer is 1/3

Method 1)
3 daughters (correct pairs daughter no. 1-a 2-b 3-c)
probability that daughter 1 will choose correct dress (i.e a) is 1/3
probability that daughter 1 will not choose a is 1- 1/3 = 2/3.
remaining dresses 2 out of which only 1 pair is correct (as first daughter picked someone else's dress)
so if either 2 or 3 pick incorrect dress with probability of 1/2 last pair is guaranteed wrong
total probability = 2/3 * 1/2 * 1 = 1/3



method 2)
let A`s dress named A, B dress named B, C`s dress named C.
Then
Total Combinations are 3!=6

A B C
A C B
C B A
B A C
B C A
C A B

Now, We have to find a condition where
A does not choose her dress,
B does not choose her dress and
C does not choose her dress.

In first four condition,
either A or B or C choose either of its right choice
like in ACB, A choose right choice... and so on
but in last two cond.
B C A
C A B
None of them chooses right choice
So fav outcome=2
and total outcome=3!=6
prob=2/6=1/3

Is this solution Helpfull? Yes (5) | No   

Pranjal Upadhyay  (11 years ago)

there's only 3 ways in which the three girls can select their dress.....and one of the way being the correct one...so there's 2 ways in which all the 3 girls will not choose their own dreeses....so the answer is 2/3.

Is this solution Helpfull? Yes (3) | No (9)  

disha verma  (11 years ago)

its 1/3 or 2/3 and how?

Is this solution Helpfull? Yes (2) | No (1)  

deepak gupta  (11 years ago)

plz explain clearly whether it's answer is 1/3 or 2/3 an how??

Is this solution Helpfull? Yes (1) | No   

venu chowdary  (11 years ago)

b)2/3 because total permutations can be made is 3p3= 6, out of those only 2 are the chances where all the three will not get their dresses

Is this solution Helpfull? Yes (1) | No (3)  

Samik Mukherjee  (11 years ago)

I don't think 1/3 is the right answer.
Reason: As per the question, at most 2 girls can choose their own dress, and not all three. There is only one way out of 6 ways where all the three girls will select their right dress. So, the required probability is: 1-1/6=5/6.

Is this solution Helpfull? Yes (1) | No (3)  

RAHUL KUMAR  (11 years ago)

ANSWER WOULD BE 1/3

Is this solution Helpfull? Yes | No (6)  

sukrati pandey  (11 years ago)

answer is 1/3 or 2/3 ?

Is this solution Helpfull? Yes | No   

sumit kumar  (11 years ago)

I think the ans is 1/6

because there is only one correct combination.....i.e A B C
in
A B C
A C B
B A C
B C A
C A B
C B A

so otal posibilities are 6 and faverable event is one....there4 ans should be 1/6

Is this solution Helpfull? Yes | No (3)  

Angel   (11 years ago)

probability of choose=1/3
probability that all will not choose=1-1/3=2/3

Is this solution Helpfull? Yes | No (1)  

sneha  (11 years ago)

total event= 3!=6
no of probability= 1/6

Is this solution Helpfull? Yes | No   

CHANDRASEKHAR  (10 years ago)

Total selections=3!=6

Proper Selections:
A B C
A C B
C B A
B A C (ie. total 4)

Improper selection: B C A , C A B (ie. total 2)
Probability for improper selection= 2/6 = 1/3

Is this solution Helpfull? Yes | No   

sindhu  (10 years ago)

answer is 1/3

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shikha raikhere  (10 years ago)

the ans is b

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RAHUL PATEL  (10 years ago)

total event= 3!=6
no of probability= 1/6

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SONAM  (8 years ago)

each girl have a chance to select only 2 dress as non of them select their own dress. so total no of selection is 6 so ans is 2/6=1/3

Is this solution Helpfull? Yes | No   

ABHISHEK MISHRA  (7 years ago)

1/3 is right ans.
total no. of ways to select the dress is 3p3=6
now let three girls are A B and C and thier respective dresses are a b and c.
as in question none of the girl select her own dress therefor only two possibilities
A>b B>c C>a
A>c B>a C>b
hence probability will be 2/6=1/3

non

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