Latest TCS Aptitude Question SOLUTION: Directions for Q. 1 to Q. 5: Refer the data: J, K, L, M and N collected stamps. They collected a total of 100 stamps. None of them collected less than 10. No two among them collect

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Number System

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40010946) TCS Numerical Ability question unsolved Keep an EYE

Directions for Q. 1 to Q. 5: Refer the data:
J, K, L, M and N collected stamps. They collected a total of 100 stamps. None of them collected less than 10.
No two among them collected the same number.
(i) 3 collected the same number as K and M together.
(ii) L collected 3 more than the cube of an integer
(iii) The no. collected by J was the square of an integer.
(iv) Total no. collected by K was either the square or cube of an integer.
1. The no. collected by J was:
(1) 27 (2) 49 (3) 36 (4) 64
2. The no. collected by K was:
(1) 16 (2) 27 (3) 25 (4) 36
3. The difference of numbers collected by L & M was:
(1) 3 (2) 2 (3) 5 (4) 9

Asked In TCS Raj Kumar (11 years ago)

Unsolved Read Solution (21)

Is this Puzzle helpful?   (34)   (15) Submit Your Solution Number System

Read Solution (21) :

urvashi  (11 years ago)

in the question it is given that j collected the square of an integer so hw can j be 27????

Is this solution Helpfull? Yes (21) | No (1)  

arvind ganesh  (11 years ago)

j=16
k=36
l=11
m=14
n=23
therefore j+l+n=k+m=50 and all the given conditions are satisfied.

Is this solution Helpfull? Yes (20) | No (14)  

kalyan  (11 years ago)

how could j be 27 as it is mentioned as square of anumber

Is this solution Helpfull? Yes (9) | No   

Jekin   (11 years ago)

Wronge question as you says, 3 collected same no as k and m together
so, we can take J+L+N = K+M = 50
then from option of J if we put any of(49, 36,or 64 as it must have square) than value of L+N will be limited to maximum 14 which is not possible...

Is this solution Helpfull? Yes (7) | No (5)  

ramana  (11 years ago)

in the question the number collected by J should be cube of the integer and l should collect 3 more than square of integer.
J+L+N=K+M
so the sum of J+L+N=K+M=50
l=3^2+3=12
so J=3^3=27
n=50-27-12=11
now k is either square or cube so possibilty are 36 or 16.and m=14 or 34
so j=27
now value for k can come after solving question 3
m-l=14-12=2 or 34-12=22
so there is 2 in option so value of m is 14 and k=36.

Is this solution Helpfull? Yes (7) | No (19)  

lala  (11 years ago)

try this....guys.and give feedback
L=11,N=12,J=27,M=14,K=36

Is this solution Helpfull? Yes (6) | No (25)  

Priyanka Vikas Sahuji  (11 years ago)

please explain

Is this solution Helpfull? Yes (3) | No (1)  

nidhi yadav  (11 years ago)

K+M=J+N+L=50
K=16;j=25;L=11;M=34;N=14

Is this solution Helpfull? Yes (3) | No (2)  

neha parween  (11 years ago)

question is wrong as it is saying that 3 collected the same number as K and M

Is this solution Helpfull? Yes (3) | No   

RAHUL KUMAR  (11 years ago)

L=12,N=11,J=27,M=14,K=36

Is this solution Helpfull? Yes (2) | No (34)  

Shivendra Bhardwaj  (11 years ago)

3 collected the same number as K and M together.
who is 3 ??

Is this solution Helpfull? Yes (2) | No (2)  

Shivendra Bhardwaj  (11 years ago)

(i) 3 collected the same number as K and M together.
(ii) L collected 3 more than the cube of an integer
what is this 3 ????????

Is this solution Helpfull? Yes (1) | No (2)  

suraj   (9 years ago)

1) J = k + l
2)3)4)--> y^2 = z^2 or z^3 + 3+x^3
this above is given part, so looking at eq. we can solve
nd get

j =36, k = 25 , l =11
j+k+l= 36+11+25=72
100-72 = 28
so, M+N = 28
but m:n = 4:3
so 4x+3x = 7x
7x= 28
x=4
m = 16
n = 12

Is this solution Helpfull? Yes (1) | No   

Raj Kumar  (11 years ago)

please explain in detail

Is this solution Helpfull? Yes | No (1)  

Nabeel Ansari  (11 years ago)

sorry question is incomplete

Is this solution Helpfull? Yes | No (1)  

harish  (10 years ago)

it is j=49
k=16
L=9
here they gave k and m are same then k=m=16 and the remaining L=9 and the difference btwn L and m =5.

Is this solution Helpfull? Yes | No   

rajasekhar  (10 years ago)

1 st condition => j+l+n=m+k
2 nd condition => L= x^3+3 =>2^3+3=11 so l=11
3rd condition => J=x^2 => i will substitute i.e less than 39 so 4^2=16
then j+l+n=16+11+n
so n=23
4th condition is k is collected squre or cube so x^2 or x^3
then 6^2=36
so m=14
then u will find out based on questions which they are asked

Is this solution Helpfull? Yes | No (1)  

karthika  (8 years ago)

pls explain the question clearly

Is this solution Helpfull? Yes | No   

Hariharan M  (8 years ago)

In this question not 3 is collected same no as k and m together it is J

Is this solution Helpfull? Yes | No   

Sandhya Velagala  (7 years ago)

plz explain in simple manner

Is this solution Helpfull? Yes | No   

Manoj B M  (2 years ago)

J=36
K=25
L=11
M=16
N=12
J=k+l
M:N=4:3

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.