Latest TCS Aptitude Question SOLUTION: p(X)=ax^4+bx^3+cx^2+dx+e has a root at x=1,2,3and4 and p(0)=48 what is p(5)?(a)48(b)24(c)0(d)50

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p(X)=ax^4+bx^3+cx^2+dx+e has a root at x=1,2,3and4 and p(0)=48 what is p(5)?(a)48(b)24(c)0(d)50

Asked In TCS jasveer (11 years ago)

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Lovejeet Singh  (11 years ago)

Ans: 48
if roots are 1,2,3,4 than
p(x)=(x-1)(x-2)(x-3)(x-4)+C
x=0
p(0)=>48=24+c
c=24
p(5)=4*3*2*1+24=48

Is this solution Helpfull? Yes (21) | No (1)  

smruthi  (11 years ago)

hey today i attened tcs xam ........its tough
hey guys .....check out train and distance ,pipes and cisterns ,time and work(5 questions)hey sudoko problem also there for every body and so on but its tough and not that easy wht we xpect..............and i am waiting for my results...

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Lovejeet Singh  (11 years ago)

@Smruthi : Please post some questions and please get in touch at lovejeet0707@gmail.com !!!!

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debopama sarkar  (11 years ago)

ans:48
p(x)=k(x+1)(x+2)(x+3)(x+4)[as 1,2,3,4 are factors)
now, p(0)=48
so k=2
so, p(5)=2(-4)(-3)(-2)(-1)
=48

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venu chowdary  (11 years ago)

1)sum of roots= -(b/a)= -48,
2)product of each two roots= (c/a)=35,
3)product of each three roots = -(d/a) = -50,
4)product of roots = (e/a) = 48,
5)on solving a=2, b= -20, c=70, d=-100, e= 48,
6)on substituting we get ans p(5)= 48.

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rishi singh  (11 years ago)

hey smruthi...plz share ur exp. at rishi69.jec@gmail.com...plz help me...

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sanjana  (11 years ago)

@smruthi : plz tel me some ques.....some ex... if u cn den mail me mainapnifavoritehoon11@gmail.com

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sunny sapra  (11 years ago)

@smruthi : plz tel me some ques.....some ex... if u cn den mail me @sunnysapra2109@gmail.com

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Subhankar Biswas  (11 years ago)

@Smruthi plz send me some new apptitude questions of tcs....my email-id:-suvo.mckvian@gmail.com

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arnab mukherjee  (11 years ago)

@Smruthi : Please post some questions and please send me at coolarnab_007@rediff.com!!!!

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nishant  (11 years ago)

please send me some questions at ch.nishantsingh007@gmail.com
Need it asap, tcs visiting in two days.

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