Latest TCS Aptitude Question SOLUTION: Raju can do a piece of work in 1o days,Vicky in 12days,Tinku in 15 days.They all started work together,but raju leaves after 2 days,vicky leaves 3 days before the work is completed

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(#M40011281) TCS Numerical Ability question time and work Keep an EYE

Raju can do a piece of work in 1o days,Vicky in 12days,Tinku in 15 days.They all started work together,but raju leaves after 2 days,vicky leaves 3 days before the work is completed. In how many days work is completed?
a)7 b)5 c)9 d)6

Asked In TCS kirankarthik (11 years ago)

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Gaurang Dhake  (11 years ago)

Work done by Raju in 1 day=>1/10
Work done by Vicky in 1 day=>1/12
Work done by Tinky in 1 day=>1/15
Initialy 3 of them work 2gether for 2 days...
One of them leaves after that working for X days...
at last only tinky remains n works for 3 days...
So
2*(1/10+1/12+1/15) + X*(1/12+1/15) + 3*(1/15)=1
Solving :x=2

Hence 2+2+3=7.
Total work was done in 7 days...:)

Is this solution Helpfull? Yes (35) | No (8)  

aryan  (10 years ago)

7.after first iteration find out work done by tinku alone in 3 days

Is this solution Helpfull? Yes (1) | No (3)  

Indranil Bose  (7 years ago)

Let the timw will taken by them to complete the whole work:x days.
raju did the work for 2 days so:2/10
vicky left the works 3 days before the work is completed,so:(x-3)/12
Tinku did the rest of the works until the last day,so:x/15
2/10+(x-3)/12+x/15=1
x=7(ANS)

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B S Surekha  (8 years ago)

total 7 days.

Is this solution Helpfull? Yes | No (2)  

Karthick  (8 years ago)

pls explain clearly

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