Latest TCS Aptitude Question SOLUTION: In an year N, the 320th day of the year is Thursday. In the year N+1 the 206th day of the year is also Thursday. What is the 168th day of In the year N-1? Options o Friday o Thursd

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(#M40011288) TCS Numerical Ability question Keep an EYE

In an year N, the 320th day of the year is Thursday. In the year N+1 the 206th day of the year is also Thursday. What is the 168th day of In the year N-1?
Options
o Friday
o Thursday
o Tuesday
o Saturday

Asked In TCS Hari Priya Kazipeta (11 years ago)

Solved ramesh Read Solution (5)

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Read Solution (5) :

ramesh  (11 years ago)

friday..If the Nth year is a non-leap year, then 320th day of year N to 206th day of year N+1 is [(365
– 320) + 206] = 251 days i.e. 35 weeks + 6 days. But this will not make the two days to be
Thursday.
Thus, the Nth year has to be a leap year. In this case 320th day of year N to 206th day of year
N+1 is [(366 – 320) + 206) = 252 days i.e. 36 weeks. Hence both days will be same day of the
week i.e. Thursday as given by the data.

168th day of N-1 year to 320th day of N year is [(365 – 168) + 320) = 517 days i.e. 73 weeks +
6 days. Thus, if the 320th day is Thursday, then the 168th day of year will be Friday, option

Is this solution Helpfull? Yes (149) | No (14)  

deviprasad gullipalli  (11 years ago)

N: 320/7=45*7 + 5 => 5th day thursday . i.e, starting day of weak is sunday

N+1: 206/7=29*7 + 3 => 3rd day is thursday . i.e, starting day is tuesday

here we get 2 odd days,,,so it is a leap year....
as (N+1)th Year is leap year, Nth, (N-1)th ,(N-2)th Can't be leap Years and so we will get 1 odd day for (N-1) th year.
Starting Day in weak for (N-1) year is saturday....
N-1: 168/7=28*7 => last day of the weak => Friday

Is this solution Helpfull? Yes (19) | No (8)  

AJAY SINGH  (11 years ago)

Friday...

Is this solution Helpfull? Yes (2) | No (5)  

Shefali Gupta  (9 years ago)

friday since
320-206=114
rem[114/7]=2
therefore 206th day in N happens to be 2 days behind thursday i.e tuesday
but in the year N+1 206th day = thursday which is 2 days after N+1 year 206th day
therefore it proves N+1 is a leap year and since leap year occurs after 4 years is N and N-1 are npt leap year
so 168th day in N-1 year is 1 day behind 168th day in N
168th day in N= 320-168=rem[152/7]=5
so it is 5 day behind 360th day i.e saturday
so 168th day in N-1 is 1 day behind 168th day in N ie.
168th day in N-1 year = friday

Is this solution Helpfull? Yes (1) | No   

Ammu  (3 years ago)

As 320th day of the N th year and 206th day of the N+1 th are same day ,i.e, Thursday,
there must be 0 odd days between these 2 days ( The number of days between these 2
days must be divisible by 7)
If N th is a non-leap year, the number of days between 2 days = (365 - 320 )+206 =251 days
Here the number of odd days in 251 days is 6 =>So Nth year must be an ordinary year
If Nth year is a leap , then the number of days between 2 days => (366 -320 ) + 206= 252 days
Number of odd days in 252 days is 0 => So we can say that Nth year a leap year.
To find the 168 th day of the year N-1, we have to find the number of odd days between the 320th day of Nth year and 168 th day of N-1 th year.
=> (365 -168) + 320 => 517 days
The number of odd days in 517 => 6 odd days
The 168th day of N-1 year is Thursday - 6 = Friday

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