Latest TCS Aptitude Question SOLUTION: two consecutive numbers are removed from the progression 1,2,3,...., n. The arithmetic mean of the remaining numbers is 26 1/4. The value of n is? 1)50 2)60 3)81 4)cannot be de

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(#M40114793) TCS Numerical Ability question numerical Keep an EYE

two consecutive numbers are removed from the progression 1,2,3,...., n. The arithmetic mean of the remaining numbers is 26 1/4. The value of n is?

1)50 2)60 3)81 4)cannot be determined

Asked In TCS Divya jain (9 years ago)

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Read Solution (2) :

kunal  (9 years ago)

n(n+1)/2 = 50*51/2 = 1275
1275-(x+x+1)/48 = 105/4
x = 7
Two consecutive no. are 7,8
Ans= 50

Is this solution Helpfull? Yes (9) | No (7)  

Abhishek Kumar  (9 years ago)

let choose from option:
take 50 as the ans
1,2,3,....50
sum= n(n+1)/2

50x51/2= 1275

if two consecutive no. are removed then
(1275-(x + x+1))/48=105/4
x=7
x+1=8
So, no. removed are 7 and 8. The correct option is 50.

Choosing other option gives you answer decimal point. Hence 50 is correct answer

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