Latest TCS Aptitude Question SOLUTION: Ram and Shakil run a race of 2000m. first, Ram gives shakil a start of 200m and beats him by 1 min. Next, Ram gives shakil a start of 6 min and is beaten by 1000m. Find the time in

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(#M40115070) TCS Numerical Ability question Time and Distance Keep an EYE

Ram and Shakil run a race of 2000m. first, Ram gives shakil a start of 200m and beats him by 1 min. Next, Ram gives shakil a start of 6 min and is beaten by 1000m. Find the time in min in which Ram and Shakil can run the race separately
a)8,10
b)10,12
c)12,18
d)10,18

Asked In TCS Divya jain (9 years ago)

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Pankaj Kr SIngh  (9 years ago)

ans >a
Let x and y are the speeds of Ram and Shakil.. Then by problem we got following equation
2000/x=(1800/y)-1
1000/X=(2000/y)-6
solve equation 1 and 2, we get x=250 and y=200
Therefore, Time taken by Ram and Shakilk to complete a race of 2000m is 8 min and 10 Min

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b  (9 years ago)

Ans is b)
1-as r gives start of 200m to s n beat him by 1min, so r covers 200m in 1min so to cover 2000m he will take 10 min
2- as r gives 6min to s n beaten by 100m means s takes 6 min to cover 1000m so he will take 12min to civer 2000m
so ans is b

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Abhishek Kumar  (9 years ago)

a/b=2000/(1800-b)=1000/(2000-6b)
2000/(1800-b)=1000/(2000-6b)
=> 4000-12b=1800-b
=>b=200

Again,
a/200=2000/(1800-200)
=>a=250

time taken by a(ram) 2000/250=8min
time taken by b(shakil)= 2000/200= 10min

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mamatha spandana parakula  (9 years ago)

D 1 =200+x D 2 =x per 1 min R-----------S---------X----------------------2000 for 1min
200 m x m
so for 1 min distence is 200+x and x their velocity are v1=(200+x) /1 v2=x/1 m/min
given if S starts 6 min beaten by 1000m =>relative velocity=1000/6
=>S covers for 1min x m =>6 min 6x
relative velocity =[(200+x)-6x]/6=1000/6
=>x=-180 from starting to 200 m then x=20m or D2=20m =>D1 220m for 1min
V1=220/1 m/min V2=20/1 m/min
=>t=D/V=> Rt=2000*1/220=100/11=9.99 min
=>st=2000*1/20=100 min

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