Latest TCS Aptitude Question SOLUTION: two cars left simultaneously from two places p & Q for Q & p respectively.they crossed each other after x hrs.after dat 1 of d car took y hrs & another took z hrs to reach their d

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(#M40011608) TCS question Keep an EYE

two cars left simultaneously from two places p & Q for Q & p respectively.they crossed each other after x hrs.after dat 1 of d car took y hrs & another took z hrs to reach their destinations.which of d following holds true?
x=(y+z)/2
x=2yz/(y+z)
x=SQRT(yz)
x=(y^2+z^2)/(y+z)

Asked In TCS Rupesh kashyap (12 years ago)

Unsolved Read Solution (6)

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Read Solution (6) :

shubham kesarwani  (12 years ago)

let car A is going from P to Q with speed a and car B is going from Q to P with speed b.
since they meet after x hr.(and let they meet at point D.)
so distance travel by car A (PD)=a*x;..........(1)
and by car B (QD)=b*x;............(2)
now car A has to cover the distance QD to reach destination
so distance(QD)=a*y;.........(3)
similarly by car B (DP)=b*z;......(4)
so by eq 1 and 4
a/b=z/x........(5)
and from 2 and 3
a/b=x/y........(6)
from 5 and 6
x=sqrt(yz);

Is this solution Helpfull? Yes (29) | No (2)  

shyamlesh dash  (12 years ago)

ans is c but can u mail me questions dear shyamleshd@gmail.com

Is this solution Helpfull? Yes (2) | No (4)  

neha mishra  (12 years ago)

A(p)----------------D--------B(q)
car a starts from p n car B from q they meet at D
so,in x hrs dist traveled by A ie AD=a*x
by BieBD=b*x
A takes y hrs more so dist ie DB =ay
n B takes ie DA=bz
now,AD=DA
so,ax=bz
ie a/b=z/x
n BD=DB
ie a/b=x/y
so.x^2=yz

Is this solution Helpfull? Yes (2) | No   

Rupesh kashyap  (12 years ago)

can u please elaborate???

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naresh  (12 years ago)

@shyamlesh dash::plz mail qns that u r having to my id:g_naresh91@yahoo.com...i have tcs on 27th..plz....

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arijit bhattacharjee  (12 years ago)

x=SQRT(YZ)

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