Latest TCS Aptitude Question SOLUTION: There are two employees in a company. One is younger and the other is older. The older employee leaves his house at 10:00 am and walks to the company with a speed of 20 metres per

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There are two employees in a company. One is younger and the other is older. The older employee leaves his house at 10:00 am and walks to the company with a speed of 20 metres per minute. After 5 minutes the younger employee also leaves his home and walks towards office with a speed of 30 metres per minute. When will he meet the older employee?

a> 11:00
b> 10:10
c> 10:15
d> 10:30

Asked In TCS suman prabhakar (11 years ago)

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Pawan Ahuja  (11 years ago)

ans is 10.15
older run till 10:05=100 younger till 10:05=0
then at 10:10=200 till 10:10=150
10:15=300 10:15=300
they meet when thr distance become equal

Is this solution Helpfull? Yes (21) | No (1)  

akshay sharma  (11 years ago)

A will travel in 100m in 5ins i.e upto 10:05
then time taken by B to travel 100m with a relative speed of (30-20)=10m
is 10mins.
i.e at 10:15am

Is this solution Helpfull? Yes (8) | No (1)  

nidhi jain  (11 years ago)

let older employee meets younger one at distance x...
now for both the distance travelled is similar i.e x...
now let older one takes y min to walk x mtrs
=> younger one takes y-5 min to walk x mtrs
=> speed of old * y = speed of young * (y-5)
=> 20y=30(y-5)
=>y=15 min
=> at 10:15 both will meet eachother...

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ajit kumar  (11 years ago)

30(x-5)=20*x
then x=15
ie after 15 min later both will meet each other

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KRUTHIKA  (11 years ago)

10.15-ans
10.00 -20 meters
10.05 -30 meters
thy vil meet at 10.15

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jayasri  (11 years ago)

older man:in 5 min----100m
younger man in 5 min-----150m
lcm of 100&150 =300m
younger 300/150=2
2*5=10min
ans:-10:15

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Rahul singh  (11 years ago)

older : younger
---------------------
10:05=100 : 10:05=0
10:10=200 : 10:10=150
10:15=300 : 10:15=300

so ans should be = 10:15

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