Latest TCS Aptitude Question SOLUTION: .A cow and a horse are bought for Rs.200000. The cow is sold at a profit of20% and the horse is sold at a loss of 10%. The overall gain is Rs. 4000.The cost pric of the cow is: a.

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(#M40012080) TCS Logical Reasoning question Keep an EYE

.A cow and a horse are bought for Rs.200000. The cow is sold at a profit of20% and the horse is sold at a loss of 10%. The overall gain is Rs. 4000.The cost pric of the cow is:
a.Rs 130000
b.Rs 80000
c.Rs 70000
d.Rs 120000

Asked In TCS Murali Ramalingam (11 years ago)

Unsolved Read Solution (21)

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Read Solution (21) :

satyavani  (11 years ago)

c+h=200000
1.2c+0 c.9h=204000
by solving it we get cp of cow as 80000

Is this solution Helpfull? Yes (47) | No (6)  

KRUTHIKA  (11 years ago)

let cost of cow be x
let cost of horse be 200000-x
so, (120%)x-(90%)(200000-x)=204000
solve the above equation vil get x=80000
thus cost price of cow is 80000/-

Is this solution Helpfull? Yes (22) | No (4)  

mgdilipsanthosh  (11 years ago)

c+h=200000
0.2c-0.1h=4000
solving these two we get c= 80000 and h=120000

Is this solution Helpfull? Yes (17) | No (2)  

Dipen jain  (11 years ago)

solve this kinda question using allegation. the most effective and the fastest way...!!
gain=4000
gain %= 400000/200000=2
cow horse
20 -10
2
12 18
cost of cow:cost of horse=12:18
=2:3
therefore cost of cow=2/5*200000=80000

Is this solution Helpfull? Yes (14) | No (3)  

packiyalakshmi  (11 years ago)

Ans: Rs.80,000

soln: go from options.
take cow cost as Rs.80000(option)
thn horse cost will be 1,20,000(2,00,000-80,000=1,20,000)
cow sold profit is 20%.
therefore 80,000 of 20% is Rs.16,000(80,000*(20/100)=16,000)
horse sold at a loss of 10%.
therefore 1,20,000 of 10% is Rs.12,000(1,20,000*(10/100)=12,000)
cow profit-horse loss=>16,000-12,000=4,000.
Rs.4000,which is the over all gain.
check it for other options we will not get overall gain of 4000Rs.

Understand the logic

Is this solution Helpfull? Yes (8) | No (4)  

ZP  (9 years ago)

use allegations method to solve this type of question

first calculate overall gain in percentage = 4000 / 200000 = 2 %

.....cow.............horse ...
.....(+20%).............(-10%)...
...................(+2%).............. use allegation
___________________________________
....(+12%)...............(18%)......


for cost price of cow is ______[ (12) / (12+18) ] * 200000 = (2/5)*200000 = 80000 ans .......... :)

Is this solution Helpfull? Yes (8) | No (1)  

Chennakrishna Rayachoti  (9 years ago)

let assume that cost of the cow is x and horse is y then
given that x+y=200000 and
(1+0.2)x+(1-0.1)y=200000+4000=204000
by solving above equations we will get x=80000 and y=120000.

Is this solution Helpfull? Yes (5) | No   

Abhishek Dash  (9 years ago)

x+y=200000
1.2x+0.9y=204000
solving this x=80000

Is this solution Helpfull? Yes (2) | No (1)  

DEEPIKA REDDY GUNUKULA  (8 years ago)

let cost of horse be x
let cost of cow be 200000-x
den gain = 0.2(200000-x)-0.1x=4000
x=1,20,000
cow cost =80,000
x=1

Is this solution Helpfull? Yes (2) | No   

Shiva Kushreshtha  (8 years ago)

x=cost of cow and y=cost of horse
then, x+y=200000
(x+20% of x)+(y-10% of y)=204000
solving the above equations we get x=80,000

Is this solution Helpfull? Yes (2) | No   

Anchal  (9 years ago)

since overall gain is 4000 so total SP= 200000+4000=204000
by forming equation,
1.2x+0.9(200000-x)=SP
Hence answer is 80000

Is this solution Helpfull? Yes (1) | No (1)  

priyam   (9 years ago)

Overall profit = 4000200000×100=2%
By applying alligation rule, we get



So cost price of the cow = 2/5 x 200000 = 80,000

Is this solution Helpfull? Yes (1) | No   

dikshant gangawat  (8 years ago)

X*1.2+(20000-X).9 -200000=4000 x=80000 i used formula gain=s.p-c.p

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Vishal Kumar  (8 years ago)

b.Rs 80000 bcoz cow profit (80000*20)/100=16000 and horse loss is (120000*10)/100=12000 so 200000+16000-12000=204000

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PANKAJ  (8 years ago)

Ans B 80000
let cow cp x
let horse cp 200000-x
then (120%of x ) - (90%of (200000-x)=200000+4000
((120/100)*x)- (90/100)*(200000-x)=204000
then u will get cp of cow = 80000

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mangaldeep kiran  (8 years ago)

Profit = 4000
Profit =SP - CP
4200=SP - 200000 therefore SP=204000
x+y = 200000
1.2x + 0.9y = 204000
Solving for x = 80000 = CP of cow.

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abhash kumar  (8 years ago)

(X*20)/100-(2000000-X)*10/100=4000
by solving it we get x=80000

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Shanakar  (8 years ago)

Let the c.p of cow be "c", Then c.p of horse will be 200000-c
s.p of cow is (120/100)*c
s.p of horse is (90/100)*(200000-c)
s.p-c.p=gain, so => (120/100)*c + (90/100)*(200000-c) - 200000 = 4000
1.2 c + 180000 - .9 c - 200000 = 4000
.3 c = 24000
=> c = 80000.
So the cost price of the cow is Rs. 80000.

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sakamuri srilakshmi  (4 years ago)

c+h=200000
gain=4000
c=120%
h=90%
(120)x-(90)(200000-x)=8000

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Kumari Aparajita  (4 years ago)

Let c=x, w=2,00,000-x
SP-CP=gain
[1.2x+(2,00,000-x)*0.9]-2,00000=4000
x=80000

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Chandramohan  (3 years ago)

It may be either 21 or 42

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