40 3 dice are rolled What is the probability that you will get the sum of the no s as

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Read Solution (11) :

nik (12 years ago)

total events = 6*6*6=216
possible cases for sum equal to 10 are
(1,3,6)-6 combinations
(1,4,5)-6 combinations
(2,3,5)-6 combinations
(2,4,4)-3 combinations
(3,3,4)-3 combinations
(2,2,6)-3 combinations
so total combinations are 27
so probability will be 27/216 = 1/8

Is this solution Helpfull? Yes (53) | No (1)

DEEPU KUMAR (12 years ago)

total no of sample space = 6*6*6=216
now,when 3 dice are rolled then to make sum 10 ,there are events like :
if 1 from 1st dice is chosen then only combination that can be chosen is 3 from 2nd dice and 6 from 3ed dice as 1+3+6=10 and so on 1+4+5,1+5+4,1+6+3 so that total 4 events if we choose 1 from 1st dice ,and similarly to 5 events if choose 2nd from 1st dice and so on 6 , 5 ,4 ,3..so total no of events =4+5+6+5+4+3=27
so probability= 27/216=.125

Is this solution Helpfull? Yes (10) | No

Satyajeet (10 years ago)

M really sorry fr the mistake in the above sol.this is the correct sol.

(1,1,1) (1,1,2) (1,1,3) (1,1,4) (1,1,5) (1,1,6)
(1,2,1) (1,2,2) (1,2,3) (1,2,4) (1,2,5) (1,2,6)
(1,3,1) (1,3,2) (1,3,3) (1,3,4) (1,3,5) (1,3,6)
(1,4,1) (1,4,2) (1,4,3) (1,4,4) (1,4,5) (1,4,6)
(1,5,1) (1,5,2) (1,5,3) (1,5,4) (1,5,5) (1,5,6)
(1,6,1) (1,6,2) (1,6,3) (1,6,4) (1,6,5) (1,6,6)
(2,1,1) (2,1,2) (2,1,3) (2,1,4) (2,1,5) (2,1,6)
(2,2,1) (2,2,2) (2,2,3) (2,2,4) (2,2,5) (2,2,6)
(2,3,1) (2,3,2) (2,3,3) (2,3,4) (2,3,5) (2,3,6)
(2,4,1) (2,4,2) (2,4,3) (2,4,4) (2,4,5) (2,4,6)
(2,5,1) (2,5,2) (2,5,3) (2,5,4) (2,5,5) (2,5,6)
(2,6,1) (2,6,2) (2,6,3) (2,6,4) (2,6,5) (2,6,6)
(3,1,1) (3,1,2) (3,1,3) (3,1,4) (3,1,5) (3,1,6)
(3,2,1) (3,2,2) (3,2,3) (3,2,4) (3,2,5) (3,2,6)
(3,3,1) (3,3,2) (3,3,3) (3,3,4) (3,3,5) (3,3,6)
(3,4,1) (3,4,2) (3,4,3) (3,4,4) (3,4,5) (3,4,6)
(3,5,1) (3,5,2) (3,5,3) (3,5,4) (3,5,5) (3,5,6)
(3,6,1) (3,6,2) (3,6,3) (3,6,4) (3,6,5) (3,6,6)
(4,1,1) (4,1,2) (4,1,3) (4,1,4) (4,1,5) (4,1,6)
(4,2,1) (4,2,2) (4,2,3) (4,2,4) (4,2,5) (4,2,6)
(4,3,1) (4,3,2) (4,3,3) (4,3,4) (4,3,5) (4,3,6)
(4,4,1) (4,4,2) (4,4,3) (4,4,4) (4,4,5) (4,4,6)
(4,5,1) (4,5,2) (4,5,3) (4,5,4) (4,5,5) (4,5,6)
(4,6,1) (4,6,2) (4,6,3) (4,6,4) (4,6,5) (4,6,6)
(5,1,1) (5,1,2) (5,1,3) (5,1,4) (5,1,5) (5,1,6)
(5,2,1) (5,2,2) (5,2,3) (5,2,4) (5,2,5) (5,2,6)
(5,3,1) (5,3,2) (5,3,3) (5,3,4) (5,3,5) (5,3,6)
(5,4,1) (5,4,2) (5,4,3) (5,4,4) (5,4,5) (5,4,6)
(5,5,1) (5,5,2) (5,5,3) (5,5,4) (5,5,5) (5,5,6)
(5,6,1) (5,6,2) (5,6,3) (5,6,4) (5,6,5) (5,6,6)
(6,1,1) (6,1,2) (6,1,3) (6,1,4) (6,1,5) (6,1,6)
(6,2,1) (6,2,2) (6,2,3) (6,2,4) (6,2,5) (6,2,6)
(6,3,1) (6,3,2) (6,3,3) (6,3,4) (6,3,5) (6,3,6)
(6,4,1) (6,4,2) (6,4,3) (6,4,4) (6,4,5) (6,4,6)
(6,5,1) (6,5,2) (6,5,3) (6,5,4) (6,5,5) (6,5,6)
(6,6,1) (6,6,2) (6,6,3) (6,6,4) (6,6,5) (6,6,6)
This is the sample space by which u can check the
sum of three dices 10
No. of fav outcomes= 27
Total no. of outcomes=216
so the probability is 27/216=1/8

Is this solution Helpfull? Yes (7) | No (3)

sattyajit mondal (12 years ago)

ans is 1/8,
total no of event is 6^3=216,
&total no of events in the sum=10 is 27,
so 27/216=1/8

Is this solution Helpfull? Yes (1) | No (4)

Satyajeet (10 years ago)

(1,1,1) (1,1,2) (1,1,3) (1,1,4) (1,1,5) (1,1,6)
(1,2,1) (1,2,2) (1,2,3) (1,2,4) (1,2,5) (1,2,6)
(1,3,1) (1,3,2) (1,3,3) (1,3,4) (1,3,5) (1,3,6)
(1,4,1) (1,4,2) (1,4,3) (1,4,4) (1,4,5) (1,4,6)
(1,5,1) (1,5,2) (1,5,3) (1,5,4) (1,5,5) (1,5,6)
(1,6,1) (1,6,2) (1,6,3) (1,6,4) (1,6,5) (1,6,6)
(2,1,1) (2,1,2) (2,1,3) (2,1,4) (2,1,5) (2,1,6)
(2,2,1) (2,2,2) (2,2,3) (2,2,4) (2,2,5) (2,2,6)
(2,3,1) (2,3,2) (2,3,3) (2,3,4) (2,3,5) (2,3,6)
(2,4,1) (2,4,2) (2,4,3) (2,4,4) (2,4,5) (2,4,6)
(2,5,1) (2,5,2) (2,5,3) (2,5,4) (2,5,5) (2,5,6)
(2,6,1) (2,6,2) (2,6,3) (2,6,4) (2,6,5) (2,6,6)
(3,1,1) (3,1,2) (3,1,3) (3,1,4) (3,1,5) (3,1,6)
(3,2,1) (3,2,2) (3,2,3) (3,2,4) (3,2,5) (3,2,6)
(3,3,1) (3,3,2) (3,3,3) (3,3,4) (3,3,5) (3,3,6)
(3,4,1) (3,4,2) (3,4,3) (3,4,4) (3,4,5) (3,4,6)
(3,5,1) (3,5,2) (3,5,3) (3,5,4) (3,5,5) (3,5,6)
(3,6,1) (3,6,2) (3,6,3) (3,6,4) (3,6,5) (3,6,6)
(4,1,1) (4,1,2) (4,1,3) (4,1,4) (4,1,5) (4,1,6)
(4,2,1) (4,2,2) (4,2,3) (4,2,4) (4,2,5) (4,2,6)
(4,3,1) (4,3,2) (4,3,3) (4,3,4) (4,3,5) (4,3,6)
(4,4,1) (4,4,2) (4,4,3) (4,4,4) (4,4,5) (4,4,6)
(4,5,1) (4,5,2) (4,5,3) (4,5,4) (4,5,5) (4,5,6)
(4,6,1) (4,6,2) (4,6,3) (4,6,4) (4,6,5) (4,6,6)
(5,1,1) (5,1,2) (5,1,3) (5,1,4) (5,1,5) (5,1,6)
(5,2,1) (5,2,2) (5,2,3) (5,2,4) (5,2,5) (5,2,6)
(5,3,1) (5,3,2) (5,3,3) (5,3,4) (5,3,5) (5,3,6)
(5,4,1) (5,4,2) (5,4,3) (5,4,4) (5,4,5) (5,4,6)
(5,5,1) (5,5,2) (5,5,3) (5,5,4) (5,5,5) (5,5,6)
(5,6,1) (5,6,2) (5,6,3) (5,6,4) (5,6,5) (5,6,6)
(6,1,1) (6,1,2) (6,1,3) (6,1,4) (6,1,5) (6,1,6)
(6,2,1) (6,2,2) (6,2,3) (6,2,4) (6,2,5) (6,2,6)
(6,3,1) (6,3,2) (6,3,3) (6,3,4) (6,3,5) (6,3,6)
(6,4,1) (6,4,2) (6,4,3) (6,4,4) (6,4,5) (6,4,6)
(6,5,1) (6,5,2) (6,5,3) (6,5,4) (6,5,5) (6,5,6)
(6,6,1) (6,6,2) (6,6,3) (6,6,4) (6,6,5) (6,6,6)

This is the sample space by which u can check the sum of three dices 10
No. of fav outcomes= 24
Total no. of outcomes=216
so the probability is 24/216=1/9

Is this solution Helpfull? Yes (1) | No (3)

ayesha siddiqui (9 years ago)

ans is 27/216.

Is this solution Helpfull? Yes (1) | No

prachitrivedi (12 years ago)

ans 13/72
3dice roll=6*6*6
no of 10 in dice roll=26

Is this solution Helpfull? Yes | No (13)

BALENDU NARAIN PANDEY (12 years ago)

1/6 as (1,3,6) can have 6 ways ...(1,4,5) have 6 way similarly (2,3,5),(2,4,4)(2,2,6),(3,3,4)..so fav condition =36&total =216 so 36/216 =1/6

Is this solution Helpfull? Yes | No (2)

Bharanidharan.S (9 years ago)

satyajeet your answer is wrong.. you see there is 27 outcomes only. not 24.. so 1/8 is the answer

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priya (8 years ago)

ans is 27/216

Is this solution Helpfull? Yes | No

Abul Barakath (8 years ago)

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