Latest TCS Aptitude Question SOLUTION: the pace length P is d distance between d rear of 2 consecutive footprints. for men d formula n/p=180 gives an approximate relation btween n & p where n = no. of steps/min p= pace

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the pace length P is d distance between d rear of 2 consecutive footprints. for men d formula n/p=180 gives an approximate relation btween n & p where n = no. of steps/min p= pace length in meters. A knows his pace length is 120cm. the formula appllies to A's walking.calculate A's walking speed in km/hr
opt:
a) 236.16
b)8.78
c)15.56
d)23.62

Asked In TCS PERACHISELVI (12 years ago)

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kaushik kishore  (12 years ago)

as n/p = 180(given), so we have p = 1.20
so n = 216steps/min
as 1 step = 1.20 m
so n = 259.2 meter/min
now n (in km/h) = 15.55

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vasu  (12 years ago)

180*60*120^2/10^7=15.55

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ria dasgupta  (12 years ago)

pace lnght of a =120cm=1.2m now n/p=180 so no of steps taken by a is n=(180*1.2)=216steps. now pace lenghth p= distance btwn 2 cnsequtve footprints=the distance covered by p during 1 footstep=1.2m so distance covered by 216 footsteps=(216*1.2)=259.2 m/min=15.55 km/hr so ans is(c)

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mukesh gupta  (12 years ago)

why 120^2 ? VASU

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