Latest TCS Aptitude Question SOLUTION: A person drive with constant speed and after sometime he sees a milestone with 2 digits.then aftr one hr, travelling with same speed sees same 2 digit in reverse order.1 hr later,h

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A person drive with constant speed and after sometime he sees a milestone with 2 digits.then aftr one hr, travelling with same speed sees same 2 digit in reverse order.1 hr later,he sees that the milestone has a same 2 digits with 0 in btwn them. what s the speed of the car?

Asked In TCS NIVETHA (12 years ago)

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Gurdeep Singh bhatia  (12 years ago)

Let the digits on the first milestone be =10x+y.
Digits on the second milestone = 10y+x
Digits on the third milestone = 100x+y.

now as the speed is constant distance covered in 1 hour will be equal between 1st,2nd milestone AND 2nd,3rd milestone!!!
therefore, (100x+y)-(10y+x)=(10y+x)-(10x+y)
108x = 18 y
(x/y)=6/1
as x and y are single digit nos. , x=6 and y=1!!!!
now milestone are 16 , 61,106 ...speed =((61-16)/1)=45kmph

Is this solution Helpfull? Yes (90) | No (1)  

deepak srivastava  (12 years ago)

Answer is 45.
as first milestone shows 16
second milestone shows 61 (61-16=45)
third milestone shows 106 (106-61=45)

Is this solution Helpfull? Yes (19) | No (7)  

Sankhadeep  (12 years ago)

helooow...if i choose.........12 and 21 and 102...it's nt same...!

Is this solution Helpfull? Yes (2) | No (3)  

BALENDU NARAIN PANDEY  (12 years ago)

ans is 45 km/hr
suppose at some time it travells by hit &trial 16 then adding 45 to it results 61 again adding 45 results 106 which fulfill required criteria.

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Gaurav Awasthi  (12 years ago)

thnx gurdeep for explaining

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