Latest TCS Aptitude Question SOLUTION: the first 44 positive integers are written in the order to form the largest number n=123456789101111213..424344. what will be the remainder when n is divided by 45?

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the first 44 positive integers are written in the order to form the largest number n=123456789101111213..424344. what will be the remainder when n is divided by 45?

Asked In TCS madhavi (12 years ago)

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ABHISHEK GROVER  (12 years ago)

no will be div by 45 when it is divided y both 9 and 5
a no is div by 9 if sum of digits is div by 9
now sum of digits of given no is 270
so the no is div by 9
and since last digit is 4 when div by 5 it leaves rem 4
let us say numbers such as 9,54...
we see they are div by 9 but leaves rem 4 when div by 5..
so when div by 45 they leave rem 9
so req ans=9

Is this solution Helpfull? Yes (23) | No (8)  

G.SOWJANYA  (12 years ago)

45 can be written as 9*5 .so chek the dividiblity rule for both 9 and 5..
and hence ans is 4

Is this solution Helpfull? Yes (7) | No (5)  

madhavi  (12 years ago)

plz confirm that is it 4 or 9?? both are in the options

Is this solution Helpfull? Yes (4) | No   

atul  (12 years ago)

can u guys pls mention options also.................

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abhi  (12 years ago)

abishek grover how can you find the remqainder 9 ............'pls explain clearly
and if you have 81 tcs pattern then pls send yaar on abhi1991002@gmail.com

Is this solution Helpfull? Yes | No (1)  

HINDUMATHI  (9 years ago)

please give the shortcut to find sum of digits... to get 270

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