Latest TCS Aptitude Question SOLUTION: Ram,shyam n hari can do a work in 8,10 n 12 days individually.if they start working together and after 2 days ram leaves and shyam leaves 3 days before the completion of work.how m

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Ram,shyam n hari can do a work in 8,10 n 12 days individually.if they start working together and after 2 days ram leaves and shyam leaves 3 days before the completion of work.how many days taken for the completion of work??

Asked In TCS atul patel (12 years ago)

Unsolved Read Solution (15)

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Read Solution (15) :

Parag Nuwal  (12 years ago)

let x be the no of days for completion of work,then
2/8+(x-3)/10+x/12=1
on solving this eq we get x=63/11 days

Is this solution Helpfull? Yes (45) | No (3)  

ashwani singh  (12 years ago)

(r+s+h) 1's day work=1/8+1/10+1/12=37/120
then 2's day work of them=2*37/120=37/60
and work done by hari in 3 day =1/12*3=1/4
so the remaning work =1-(37/60+1/4)=2/15
sayam and hari 1's day work=(1/10)+(1/12)=11/60
then no of day to compleate remaning work(2/15) is =(60/11)*(2/15) = 8/11 day
then the totel no of day =2+3+(8/11) = 5+(8/11) =63/11 is ryt ans.

Is this solution Helpfull? Yes (33) | No   

dharmveer  (12 years ago)

sorry it will be 63/11 @pankaj take 150 instead of 120 so he got remaining as 46 which should be 16

Is this solution Helpfull? Yes (9) | No   

PANKAJ ARORA  (12 years ago)

take Lcm of 8,10,12 which is 120..so assume 120 units of work,,
ram do 15 units per day..
shyam do 12 units per day
hari do 10 units per day
so if they work together 37 units of work wil be one per day..after 2 days whn ram leave
74 units of work wil be finishd
remaining work wil be 150-74=76

in last 3 days only hari works
so hari can do 30 units of work in last 3 days
remaining work is 76-30=46
which ws done by shyam n hari togethr in 46/22 days so in all
2+3+ (23/11)=78/11 days are req to complete the wrk

Is this solution Helpfull? Yes (5) | No (5)  

prateek agarwal  (12 years ago)

2/8+(x-3)/10+x/12=1
on solving the above equation
x=63/11

Is this solution Helpfull? Yes (4) | No   

ashwani singh  (12 years ago)

(r+s+h) 1's day work=1/8+1/10+1/12=37/120
then 2's day work of them=2*37/120=37/60
and work done by shyam=1/8*3=3/8
so the remaning work =1-(37/60+3/8)=1/12
sayam and hari 1's day work=(1/10)+(1/12)=11/60
then no of day to compleate remaning work(1/12) is =(60/11)*(1/12) = 5/11 day
then the totel no of day =2+3+(5/11) = 5+(5/11) =60/11 is ans

Is this solution Helpfull? Yes (3) | No (5)  

preeti arya  (12 years ago)

ans is 63/11.......

Is this solution Helpfull? Yes (2) | No (2)  

shashank dubey  (12 years ago)

2/8 +(x-3)(1/10 +1/12)+3/12 =1
x=78/11

Is this solution Helpfull? Yes (1) | No (5)  

Meenal Dugar  (12 years ago)

let x be the total no. of days
x/12 + (x-2)/8 + (x-3)/12 = 1
x=186/47

Is this solution Helpfull? Yes (1) | No (3)  

dharmveer  (12 years ago)

53/11 is answer

Is this solution Helpfull? Yes | No (9)  

PANKAJ ARORA  (12 years ago)

sory for my mistake yr ...it wil be 120 instead of 150...

Is this solution Helpfull? Yes | No (2)  

Angel   (12 years ago)

i think 60/11 option plz...............

Is this solution Helpfull? Yes | No (4)  

rajapaul  (12 years ago)

s=12+9.8+3.6=25.4

Is this solution Helpfull? Yes | No (3)  

venkatrao  (12 years ago)

let x be the no of days for completion of work,then
2/8+(x-3)/10+x/12=1
on solving this eq we get x=63/11 days

Is this solution Helpfull? Yes | No (4)  

sachin  (12 years ago)

answer is 7 days

Is this solution Helpfull? Yes | No (1)  

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