Latest TCS Aptitude Question SOLUTION: 3 dice are thrown. Find probability of sum = 10?

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(#M40012737) TCS question Keep an EYE

3 dice are thrown. Find probability of sum = 10?

Asked In TCS rinky das (11 years ago)

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Sahil Motwani  (11 years ago)

for such type of questions the method is seen to be time consuming
so we can learn a simple series for rolling of three dices
•Probability of a sum of 3: 1/216
•Probability of a sum of 4: 3/216
•Probability of a sum of 5: 6/216
•Probability of a sum of 6: 10/216
•Probability of a sum of 7: 15/216
•Probability of a sum of 8: 21/216
•Probability of a sum of 9: 25/216
•Probability of a sum of 10: 27/216
•Probability of a sum of 11: 27/216
•Probability of a sum of 12: 25/216
•Probability of a sum of 13: 21/216
•Probability of a sum of 14: 15/216
•Probability of a sum of 15: 10/216
•Probability of a sum of 16: 6/216
•Probability of a sum of 17: 3/216
•Probability of a sum of 18: 1/216

Is this solution Helpfull? Yes (20) | No (1)  

rahul  (11 years ago)

possible solution
(1+3+6),(1+4+5),(1+5+4),(1+6+3)=4
(2+2+6),(2+3+5),(2+4+4),(2+5+3),(2+6+2)=5
(3+1+6),(3+2+5),(3+3+4),(3+4+3),(3+5+2),(3+6+1)=6
(4+1+5),(4+2+4),(4+3+3),(4+4+2),(4+5+1)=5
(5+1+4),(5+2+3),(5+3+2),(5+4+1)=4
(6+1+3),(6+2+2),(6+3+1)=3
possible combination=(4+5+6+5+4+3)=27
now possible combination is (6*6*6)=216
probabitity=27/216

Is this solution Helpfull? Yes (13) | No   

praveen kumar  (11 years ago)

fist we find total no of combination..
clearly..we have 3 place i.e - - -,we can fill the place using digit 1 to 6 but sum must be 10..
(1 3 6)--6 ways
(1 4 5) 6 ways
(2 2 6) 3 ways
(2 3 5) 6 ways
(2 4 4) 3 ways
(3 3 4) 3 ways
total-27 ways
p=27/216

Is this solution Helpfull? Yes (8) | No   

venkatesh bollam  (11 years ago)

Ans 27/216 is it correct

Is this solution Helpfull? Yes (5) | No (2)  

venkatrao  (11 years ago)

If r=10,r=11 then p=27/2*6^3

Is this solution Helpfull? Yes | No (6)  

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