Latest TCS Aptitude Question SOLUTION: There are 720 boxes to be moved by G, M & H. G & M takes 24 days; M & H takes 30 days; H & G takes 36 days. If G works 4 days, M for 8 and H for 8 days. How much work completed?

• Placement Papers
• /
• TCS

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40012782) TCS question tcs question Keep an EYE

There are 720 boxes to be moved by G, M & H. G & M takes 24 days; M & H takes 30 days; H & G takes 36 days. If G works 4 days, M for 8 and H for 8 days. How much work completed?

Asked In TCS chandan kumar (11 years ago)

Unsolved Read Solution (5)

Is this Puzzle helpful?   (0)   (0) Submit Your Solution

Read Solution (5) :

Sahil Motwani  (11 years ago)

244 boxes will be moved.
as gm take 24 days to do work so 1 days work is 1/24 so boxes moved in one day is equal to (1days work)*720=720/24=30 boxes. similarly mh move 24 boxes in one day and hg move 20 boxes in one day. so gmh together move (30+24+20)/2 boxes in one day= 37.
so boxes moved by g = 37-24=13
boxes moved by h = 37-30=7
boxes moved by m = 37-20=17
thus work completed= 13*4+17*8+7*8(as they work 4,8,8 days respectively)
=244 boxes

Is this solution Helpfull? Yes (65) | No (1)  

s.jaweed hussain  (11 years ago)

27*4+21*8+9*8=348 boxes.....

Is this solution Helpfull? Yes (4) | No (5)  

srikhakollu bharghav  (11 years ago)

i think answer is...244 boxes...is it correct mr.chandan kumar?

Is this solution Helpfull? Yes (2) | No (2)  

taruna  (11 years ago)

ans is 244!

Is this solution Helpfull? Yes (2) | No (2)  

saurav khandelwal  (11 years ago)

g+m=24,m+h=30,h+g=20,let there lcm be the total work ,so g+m completes 30 parts,m+h complets 24 parts,h+g complets 20 parts.so 2*(g+h+m)=74parts,g+h+m=37 so comparing it with g+m=30 parts so h do 7 parts in one day so like that g complete 13 nd m-17 parts in one day now in respective days so 56+52+136 by
h,gnd m respectively..

Is this solution Helpfull? Yes (1) | No (2)  

Please Login to Read Solution.