Latest TCS Aptitude Question SOLUTION: 1 2 2 3 3 3 4 4 4 4 1 1 2 2 2 2 3 3 3 3 3 3 4 4 4 4 4 4 4 4 ..................what is the 2852 term? wit xplanation

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1 2 2 3 3 3 4 4 4 4 1 1 2 2 2 2 3 3 3 3 3 3 4 4 4 4 4 4 4 4 ..................what is the 2852 term? wit xplanation

Asked In TCS piyushkumar (11 years ago)

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riddhi soni  (11 years ago)

each time the number become double their strength jst as 10 20 40....and soon so wehve to find the last limit as 10 20 40 80 160 320 640 1280 total 2550
here ratio they are incrementing is 1:2:3:4 always in 1280 the no of 1s 2s 3s nd 4s is as 128:256:384:512
so what left is 2852-2550=302
no of 1s in next iteration ll b jst double of previous eg 128*2=256
and no of 2s ll be 512
so substractin 302 -256= will give range for 2
ans is 2

Is this solution Helpfull? Yes (15) | No (2)  

Pritam  (11 years ago)

D series is from first 1 to last 4 is 10 no's, d series is 10,20,30.... 2852/10= 28 th series, 2801 th wld b 1, 28 times, so, 2829th to 2857 wuld be 2..
So, d ans is 2..

Is this solution Helpfull? Yes (3) | No (2)  

ramya  (11 years ago)

ans: 4
10+20+30+...+2852
10n(n+1)/2=2852
then n=24
apply n value to n(n+1)/2 then get 3000
24*4=96.then in last part has 96 4's. 3000-2852=72 then 2852 is a 72 4.

Is this solution Helpfull? Yes (1) | No (7)  

Sourav Bandyopadhyay  (11 years ago)

i think ans is 3......
sorry due to net problem i can't explain

Is this solution Helpfull? Yes (1) | No (2)  

akhil kogta  (11 years ago)

i think ans will be 3
As 10+20+30.....=2852
10*n(n+1)/2=2852
solving n=24
as 111....24times2222....48times3333....72times so
24+48+20=92 so 3 will be ans.

Is this solution Helpfull? Yes (1) | No   

varun mishra  (11 years ago)

ans should be 1
for n=1 no of terms= 10
n=2 terms= 20
2800 terms for n= 280
then 2852 we get by n=281 so there will be 281 1s
from 2801 to 3081 there will be 1 so 2852 term is 1.

Is this solution Helpfull? Yes | No (4)  

Sourav Bandyopadhyay  (11 years ago)

10+20+30+...+2852
10n(n+1)/2

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