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(#M40001305) SYNTEL Numerical Ability question Keep an EYE

Find the number of sides of a regular convex polygon whose angle
is 40degrees.

Asked In Syntel suneil (14 years ago)

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Saurabh Dua  (14 years ago)

if the polygon s of n sides then the interian angle is given by (n-2)*180/n.
so (n-2)180/n =40.
we get n=18/7..since n is a integer so we conclude that no such polygon is posible..

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deepika  (14 years ago)

(n-2)*180/n.............zero

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himanshu singh  (14 years ago)

answer is 9

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sachin kumar  (14 years ago)

The measure of one vertex angle of a regular polygon is given by:
%28n-2%29180%2Fn where n is the number of sides of the regular polygon...and, of course, it goes without saying, that n must be an integer >2(i.e, 3, 4, 5, 6, ...).
If the measure of one vertex angle of a regular polygon is 40 degrees, then we can write:
%28n-2%29180%2Fn+=+40 Simplify and solve for n.
%28180n-360%29%2Fn+=+40 Multiply both sides by n.

180n+-+360+=+40n Add 360 to both sides.
180n+=+360%2B40n Subtract 40n from both sides.
140n+=+360 Divide both sides by 140.
n+=+2.57 This is not possible since a regular polygon mu

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