Latest TCS Aptitude Question SOLUTION: probability of getting a total of atleast 5 when 2 dice are thrown

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probability of getting a total of atleast 5 when 2 dice are thrown

Asked In TCS charan (11 years ago)

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mohd zubair khan  (11 years ago)

(sorry this solution uploaded by mistake)
now correct solution-----
first tatal ways of outcomes = 36
now we have two ways to calculate a total of atleast 5:
1. either calculate all outcomes whose some is either eqaual to or greater than
five.
2. calculate all outcomes whose some is less than 5 and subtract from 36

so 2nd one is easy
tatal outcomes = less than five = (1,3),(3,1),(2,2,),(1,2),(2,1),(1,1)
= 6 outcomes
for atleast five = 36 - 6 = 30
so probability of outcomes atleast five= 30/36 =5/6 ans

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Manisha Bishoye  (11 years ago)

total outcomes=6*6=36
atleast 5 means we can get the sum as 5 or more than 5
hence for easy calculation we can find the sum where we cant get 5 and subtract it from 1 which is the total probability
outcomes where we dont get a 5 is (1,1)(1,2)(1,3)(2,1)(2,2)(3,1)= 6 outcomes
=>1-(6/36)=1-(1/6)
=5/6 (ans)

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Narendra Kumar  (11 years ago)

probability of happening an event =1-(probability of not happening the event)
so probability of getting at least 5=1-(probability of not getting at least 5)
That means we need to find probability of getting 1 or 2 or 3 or 4.
for 2 (1,1)
for 3 (1,2),(2,1)
for 4 (1,3),(3,1),(2,2)
total cases=6
so probability of getting at least 5 = 1-(6/36) = 5/6

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sayanti mondal  (11 years ago)

unfavorable outcomes are6[(1,1)(1,2)(1,3)(2,1)(2,2)(3,1)]
thus favrbl output=total outcomes-unfavourable[36-6]=30
so probability=30/36=5/6

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mohd zubair khan  (11 years ago)

a total of 5 can be viewed as = (1,4),(4,1)(2,3),(3,2) = 4 ways
to tatal ways of outcomes= 6x6 = 36
so probability = 4/36 = 1/9 (ANS)
(you feed back is valuable to me)

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saurabh kushwah  (11 years ago)

when 2 dice are thrown simultaneously .total events=36 favourable events=18 bcoz
no. more than
(2,3) (3,2),(4,

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PRABHAT KUMAR  (11 years ago)

n(s)=36 ,cause sample space of thrown two dice is6*6=36
nd chances of getting less than 5 is(1,1),(1,2),(1,3),(2,1),(2,2),(3,1)
so the probability of getting less than five is 6/36=1/6
probability=1-1/6=5/6;

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