Latest Infosys Aptitude Question SOLUTION: How many integers between 0 and 1000 DO NOT contain the integer 1

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How many integers between 0 and 1000 DO NOT contain the integer 1

Asked In Infosys praveen (11 years ago)

Solved Garima Read Solution (10)

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Read Solution (10) :

Amod Kumar Lal  (11 years ago)

from 1 to 99 = 19 integers having 1
from 101 to 199 = all are having 1
similarly 201-299, 301-399, 401-499,.....so on, will have 19 integers having 1

Answer = 1000 - (19*9 + 99 + 2) // 2 is added for 100 and 1000
= 728

Is this solution Helpfull? Yes (17) | No (6)  

Garima  (11 years ago)

Base 9 will have 9^3 = 729 numbers from 0-999.
here integers between 0 and 1000 are required.
so Zero is excluded.
rest 729-1=728 numbers will not have digit 1.

Is this solution Helpfull? Yes (13) | No (4)  

Garima  (11 years ago)

728 integers between 0 and 1000 do not contain integer 1.

Is this solution Helpfull? Yes (3) | No (1)  

Vishesh Goswami  (7 years ago)

Total no. of integers between 0 and 1000 = 999
By per and comb ,
1 digit number not containing number '1' = 8
2 digit number not containing number '1' = 72
3 digit number not containing number '1' = 648
Therefore ,total number of integers nit containing '1' = 648 + 72+ 8 = 728

Is this solution Helpfull? Yes (3) | No   

Abhradeep Ganguli  (10 years ago)

799. because from 0-100 it is 80, 101 to 999 it is 719. thus 719+80=799

Is this solution Helpfull? Yes (1) | No   

praveen   (11 years ago)

is there any relevant formula garima??

Is this solution Helpfull? Yes | No (2)  

subhradeep ganguli  (10 years ago)

728
101 to 199 contains 100 numbers having 1 in it.. 0-99, 200-299 and so on each contains 19 numbers having 1 in it.. again 1000 has 1 in it.. so answer is
{1000-((19*9)+100)}-1=728

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keerthana chennamsetty  (9 years ago)

the answer is 271

Is this solution Helpfull? Yes | No (1)  

chandraday bhowmik  (7 years ago)

271.. 1 to 99 -19 no
among 100to 999 suppose no no having 1 so such combination 8*9*9=648
so having 1 900-648=252
total 252+19=271

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SHUVAM KANGSABANIK  (7 years ago)

Answer = 709

1 to 99 = 19 integers have 1
100 has 1
101 to 199 = 99 has 1
201-299, 301-399, ....901-999 has 19 each
100 has 1

total number of integers from 0 to 1000 having 1 = 19 + 1 + 99 + 19*9 + 1 = 291
Required ans = 1000 - 291 = 709

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