Latest SSC Aptitude Question SOLUTION: A and B each working alone can do a work in 15 days and 25 days respectively. They started the work together, but B left after some time and A finished the remaining work in 7 days

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(#M40013504) SSC Numerical Ability question time and work Keep an EYE

A and B each working alone can do a work in 15 days and 25 days respectively. They started the work together, but B left after some time and A finished the remaining work in 7 days. After how many days from the start did B leave?

Asked In SSC jatinder (11 years ago)

Solved Rakesh Kumar Kohli Read Solution (4)

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Read Solution (4) :

Rakesh Kumar Kohli  (11 years ago)

A can finish work in 1 day = 1/15
B can finish work in 1 day = 1/25
Both A & B can finish work in 1 day = 1/15 + 1/25 = 8/75
Part of the work A alone finished in 7 days = 7/15
Part of work A & B together finished = 8/15
So A & B together finished the 8/15 of the work in = (8/15)/(8/75)= 5 days
So B left from the start of the work after 5 days.

Is this solution Helpfull? Yes (16) | No (1)  

Amit kumar  (11 years ago)

total work= LCM(15,25)=75 units work
A can do 15 days work= 75 units work
===> 1 days work= 75/15=5 units work

B can do 25 days work= 75 units work
===> 1 days work= 75/25=3 units work

Both A and B can do 1 day work= 5+3=8 units work.
let B left after x days
Complted work = workdone by both= 8x
remaining work work done my A= 7*5
Completed work + Remaining work = Total work
===> 8x+7*5=75
===> x=5 days

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Durgesh tiwary  (11 years ago)

A completes 100/15 = 6.66 %
B '''''''' 100/25 = 4%
A work 7 days so it completes 6.66*7 = 44.42%
Remaining work done by A+B ( 6.66% + 4% = 10.66) which is 56 % approx
so for these work AB takes 10.66*5 = 53% so Ans = 5 days

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Anuj Katiyal  (11 years ago)

great soln rakesh

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