Latest MBA Aptitude Question SOLUTION: In the quadrilateral ABCD, ∠BAD = ∠BCD = 90°. If AE = 6 cm, CE = 15 cm and DE = 10 cm, find the length of BF.

1) 9
2) 8
3) 10
4) 15

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Previous Question: Tenengineering employees from IMPERIAL Business School namely Akhil, Bahadur, Cheteshwar,Dheeraj, Eli, Fatima, Gautam, Hemant, Inder and Jai joined a Finance firm as atrainee. The firm selected some of them to go to USA and Netherland forattending two seminars on new advances in stock market, to be held in the monthof January and February 2012 respectively in such a way that at least 5 wereselected for USA and at least 5 were selected for Netherland. 1.If Akhil and Bahadur were selected for differentcountries, then what is the maximum number of trainees who were selected forUSA?(a)6(b)5(c)8(d)32. The following conditions apply:• Cheteshwar and Dheeraj were selected for both the countries.• Bahadur and Jai were not selected for the same country.• Eli and Gautam were selected for at least one country.• Hemant was selected for Netherland only.• If Inder was selected for both the countries then Eli and Fatima would also have been selected for both the countries.• Akhil was selected for any one of the two countries but not for both the countries.

1) 6
2) 5
3) 8
4) 3
Next Question: Vishal was given a task to distribute 400 gifts amongst 11 people in such a manner that no two people get same number of gifts and no two pairs of any two people should have same number of gifts and Vishal could take remaining gifts himself. What is the maximum number of gifts that Vishal can get?

1) 25
2) 144
3) 169
4) 151
5) 172

(#M40014071) MBA question mensuration, geometry & co-ordinate geometry Keep an EYE

In the quadrilateral ABCD, ∠BAD = ∠BCD = 90°. If AE = 6 cm, CE = 15 cm and DE = 10 cm, find the length of BF.

1) 9
2) 8
3) 10
4) 15
5) 20

Asked In MBA (12 years ago)

Unsolved Read Solution (1)

Is this Puzzle helpful?   (7)   (1) Submit Your Solution

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Read Solution (1) :

tejashwi kumar  (10 years ago)

consider triangle CED,
tan(angleDCE)=10/15=2/3
now consider triangle CBF,
tan(90-angleDCE)=BF/CF => BF=(3/2)*CF -----------1)
Now consider triangle ADE,
tan(angle DAE)=10/6=5/3
consider triangle ABF,
Tan(90-angleDAE)=BF/AF => BF=(3/5)*AF ----------2)
equating 1) & 2) , we get AF=(5/2)*CF ----------3)
But AF+CF=21 => CF=6 cm
Putting the value of CF in 1) , we get BF= 9 cm

Is this solution Helpfull? Yes (1) | No   

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Previous Question: Tenengineering employees from IMPERIAL Business School namely Akhil, Bahadur, Cheteshwar,Dheeraj, Eli, Fatima, Gautam, Hemant, Inder and Jai joined a Finance firm as atrainee. The firm selected some of them to go to USA and Netherland forattending two seminars on new advances in stock market, to be held in the monthof January and February 2012 respectively in such a way that at least 5 wereselected for USA and at least 5 were selected for Netherland. 1.If Akhil and Bahadur were selected for differentcountries, then what is the maximum number of trainees who were selected forUSA?(a)6(b)5(c)8(d)32. The following conditions apply:• Cheteshwar and Dheeraj were selected for both the countries.• Bahadur and Jai were not selected for the same country.• Eli and Gautam were selected for at least one country.• Hemant was selected for Netherland only.• If Inder was selected for both the countries then Eli and Fatima would also have been selected for both the countries.• Akhil was selected for any one of the two countries but not for both the countries.

1) 6
2) 5
3) 8
4) 3
Next Question: Vishal was given a task to distribute 400 gifts amongst 11 people in such a manner that no two people get same number of gifts and no two pairs of any two people should have same number of gifts and Vishal could take remaining gifts himself. What is the maximum number of gifts that Vishal can get?

1) 25
2) 144
3) 169
4) 151
5) 172

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