Latest exam Aptitude Question SOLUTION: (6x^3+23x^2+27x) divided by (2x+3)

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Previous Question: How do you solve for each variable: (x-3)(x-7)=0 b^2+3b-4=0 n^2+n-12=0 5x^2+18x=8 3a^2+4a=2a^2-2a-9 Next Question: a rectangular piece of paper has a width of 16 inches and an area of 192 square inches. what is its length?

(#M40144854) EXAM Numerical Ability question Keep an EYE

(6x^3+23x^2+27x) divided by (2x+3): Asked In exam (9 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Previous Question: How do you solve for each variable: (x-3)(x-7)=0 b^2+3b-4=0 n^2+n-12=0 5x^2+18x=8 3a^2+4a=2a^2-2a-9 Next Question: a rectangular piece of paper has a width of 16 inches and an area of 192 square inches. what is its length?

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