Latest Elitmus Aptitude Question SOLUTION: in how man ways can 10 identical presents be distributed among 6 children so that each gets at least one present. a)15c5 b)16c6 c)9c5 d)6 ^ 10

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(#M40151347) ELITMUS Numerical Ability question Keep an EYE

in how man ways can 10 identical presents be distributed among 6 children so that each gets at least one present.
a)15c5
b)16c6
c)9c5
d)6 ^ 10

Asked In Elitmus (9 years ago)

Unsolved Read Solution (10)

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siddharth prakash singh  (9 years ago)

No of ways of dividing n identical things among r different group(for non empty set i.e, each one get at least one) is given by (n-1)C(r-1)
so on applying this to given situation we get. 9c5

Is this solution Helpfull? Yes (25) | No (2)  

sriram vinay  (9 years ago)

ans is 9C5 bcz in question they have mentioned that each child get atleast one present so, first distribute 6 presents to 6 childrens remaining is 4 presents(n=4) now apply formula (n+r-1)C(r-1) (4+6-1)C(4-1) =9C5

(n+r-1)C(r-1) is used when n identical things are distributed to r people where each can get either 0 or more presents

Is this solution Helpfull? Yes (5) | No   

shubham jain  (9 years ago)

totel=10
remaing r=10-6=4
n+r-1Cr+1= 6+4-1C4+1
9C5

Is this solution Helpfull? Yes (2) | No (2)  

soni kumari  (9 years ago)

since presents are identical
can be distributed in 6^10 ways

Is this solution Helpfull? Yes (2) | No (5)  

rohit bisht  (9 years ago)

sorry but answer should be like dividing n identical things among r different group=(n+r-1)C(r-1)
which will come out as 15C5
so (a) correct choice

Is this solution Helpfull? Yes (1) | No (3)  

Ankesh Verma  (9 years ago)

here n=10 & r= 6
we want to distribute identical presents among 6 children each gets at least one present n-1cr-1.
9c5 is answer

Is this solution Helpfull? Yes (1) | No   

shravan kumar jha  (9 years ago)

ans- 9c5
concept is find the no. of positive integeral solutions of equation- x1 + x2 + x3 + x4 + x5 + x6 = 10
is-9c5 [ (10-1) c (6-1) ]

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Shree Govind Mishra  (9 years ago)

consider it like this....
x+x+x+x+x+x = 10
ie each of them should receive atleat one and could receive more than one...
(n-1)C(r-1)

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rahul kumar  (8 years ago)

it is a situation of distributon of n identical objetc among r groups such that every one must get atleast one object=>
"n-1Cr-1"
=> (10-1) C(6-1)
=> 9C5

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Kottakota bharat  (5 years ago)

9c5 answer

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