Latest C Aptitude Question SOLUTION: main() { int i=5,j; j = i++ + ++i + ++i + ++i; printf("%d",j); }

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(#M40151459) C question c program Keep an EYE

main()
{
int i=5,j;
j = i++ + ++i + ++i + ++i;
printf("%d",j);
}

Asked In C saranya (10 years ago)

Unsolved Read Solution (34)

Is this Puzzle helpful?   (10)   (4) Submit Your Solution undefined

Read Solution (34) :

Akanksha Shrivastava  (10 years ago)

j=5+7+8+9
hence j= 29

Is this solution Helpfull? Yes (18) | No (3)  

pratiksha sachan  (10 years ago)

j = i++ + ++i + ++i + ++i;
i++ will increment the value of i, but return the original value that i held before being incremented.
++i will increment the value of i, and then return the incremented value.
j = 5+7+8+9
j =29

Is this solution Helpfull? Yes (7) | No (1)  

seshunaga  (9 years ago)

j = i++ + ++i + ++i + ++i;
let post increment keep aside, then expression becomes
j = i + ++i + ++i + ++i;
then evaluate the expression consider the priorities
i.e i-> 5 -> 6-> 7-> 8
substituting the value in the final expression after implementing the all pre-increment operator i.e Right TO Left.
finally i becomes 8, then substitute the value in the remaining expression
j = 8 + 8 + 8 + 8
i.e j=32
the post increment should be consider finally to variable i,
i becomes i++ final value of i is 9.
the output of the program will be

9 32

better to consider memory blocks for variables for easy understanding.

Is this solution Helpfull? Yes (6) | No   

ashvini kumar  (10 years ago)

j=6+6+7+8
=27

Is this solution Helpfull? Yes (2) | No (2)  

ankur malik  (10 years ago)

It is compiler dependent, so no correct answer can be given,,

Is this solution Helpfull? Yes (2) | No   

SELVAVIGNESH>M  (9 years ago)

j=i++ + ++i + ++i + ++i
step1:
++i=6
++i=7
++i=8
now i=8;
step 2:
y=i+i+i+i;
y=28;
step 3:
i++=9
i=9

Is this solution Helpfull? Yes (2) | No   

Shivani Saxena  (10 years ago)

follows preorder - algebra -postorder
output- 32

Is this solution Helpfull? Yes (1) | No (1)  

Parvathaneni Sailakshmi  (9 years ago)

6+7+8+9=30

Is this solution Helpfull? Yes (1) | No (1)  

jaya  (9 years ago)

6+6+7+8=27

Is this solution Helpfull? Yes (1) | No (1)  

krishna  (9 years ago)

j=5+7+8+9
hence j= 29

Is this solution Helpfull? Yes | No   

kumar atul  (9 years ago)

I THINK IT SHOULD BE COMPILLER ERROR BECAUSE I WILL STATRT WORKING FROM LEFT OR RIGHT IT DEPENDS ON COMPILLER

Is this solution Helpfull? Yes | No (1)  

Nipun Gupta  (9 years ago)

j= 5+7+8+9=29

Is this solution Helpfull? Yes | No (2)  

ROHIT PANDEY  (9 years ago)

the value in post increment is incremented after semi colon but in pre increment the value increases at the same place ........before semicolon of the second statement value of x is pre incremented 3 times so i=5+1+1+1 ie 8..now the statement means j=8+8+8+8 ie 32 and after semicolon the post incrementation will take place and value will i will become 9.......so output of program will be 32

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PRITI MISHRA  (9 years ago)

output will be 32

Is this solution Helpfull? Yes | No (1)  

shubham  (9 years ago)

j=5+7+8+9

answer is j=39

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neha choudhary  (9 years ago)

j=5+ 7+ 8 +9 =29

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ashutosh tiwari  (9 years ago)

j = 32
i = 9

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Mahabir kumar gorain  (9 years ago)

ans is 32.
this is register evaluation,it works with priority i.e.,pre operator has higher priority than post operator.
In register evaluation data need to substituted after modifying all pre values.
j=8+8+8+8=32 (3 pre operator )

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anisha chitturu  (9 years ago)

21...i++ means it will be incremented before the excecution of that statement and ++i means it will be incremented after the excecution of that statement so 6+5+5+5=21

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salil  (9 years ago)

if copiler is 16 bit the ,,, ans = 16
if compier is 32 bit ,,,,,,, ans = 32

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Shinjaa  (9 years ago)

i=5

++i=7
++i=8
++i=9
ans:5+7+8+9=29

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Kundan Gope  (9 years ago)

j=5+7+8+9=29

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Prasenjit Mahanta  (9 years ago)

Answer must be 27
6+6+7+8=27

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DARISA VENKATA SUNIL MITHRA   (9 years ago)

j=29
I dont know the reason

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MATLOOB HUSAIN  (9 years ago)

Associatibity of increament operator is become from right to left so according to this rule value of this is 27

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Rakhi Modi  (9 years ago)

j=5+7+8+9=29

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Vanitha  (9 years ago)

doesnot space between the incerment and + operator it gives an error bad operand

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satish kumar suman  (9 years ago)

u can not pridict the output unless compiler is provided
same code will generate different output on different compilers like dev c,turbo c, and so on

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Neha Saini  (9 years ago)

ans is 27
j = 5 + 7 + 8 + 9

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Amit Bansal  (9 years ago)

since arithmetic operation are evaluated from left to right, and unary are evaluated from right to left..
j=(((i++ + ++i) + ++i )+ ++i)
j=((( 6 + 6) + ++i)+ ++i) -->i=7
j=((12 + 8)+ ++i) --> i=8
j=20 + 9
j=29

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vivek  (9 years ago)

5+6+7+8
28

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KOTGADY RAJU  (9 years ago)

Undefined symbol J

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kaushal  (8 years ago)

It will just like j=5+7+8+9(29)

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SANDEEP KUMAR  (7 years ago)

Actually, it depends on the compiler
according to one compiler
i is pre-incremented 3 times so i becomes 8 and that 8 will be placed in the place of i so
j=8+8+8+8==>32
according to another compiler
j=5+7+8+9==>29

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