Latest TCS Aptitude Question SOLUTION: 6)Find the smallest number in a GP whose sum is 38 and product 1728 (a) 12 (b) 20 (c) 8 (d) none of these

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6)Find the smallest number in a GP whose sum is 38 and product 1728

(a) 12
(b) 20
(c) 8
(d) none of these

Asked In TCS vaishali rathore (8 years ago)

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Read Solution (2) :

ABHISEK CHATTARAJ  (8 years ago)

Sum of these numbers are:
a/r +a +ar = 38
a(1r+1+r) = 38 ---- (1)
Product of these numbers are:
a^3 = 1728
= (12)^3
a = 12

Putting the value of a in (1) you will get:

12(1r+1+r) = 38

And factorising, we get
r = 2/3 or r = 3/2

Sub. the r and a value in (A), we get

8,12,18 or 18,12,8. When a = 12

And smallest no. is 8.

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prabhat kumar  (8 years ago)

8
8* 3/2=12
12*3/2=18
8+12+18=38
8*12*18=1728

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