Latest TCS Aptitude Question SOLUTION: In the town of Unevenville, it is a tradition to have the size of the front wheels of every cart different from that of the rear wheels. They also have special units to measure c

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In the town of Unevenville, it is a tradition to have the size of the front wheels of every cart different from that of the rear wheels. They also have special units to measure cart wheels which is called uneve. The circumference of the front wheel of a cart is 133 uneves and that of the back wheel is 190 uneves. What is the distance traveled by the cart in uneves, when the front wheel has done nine more revolutions than the rear wheel?
a. 570
b. 1330
c. 3990
d. 399

Asked In TCS Avantika Verma (8 years ago)

Unsolved Read Solution (9)

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Read Solution (9) :

samarth shrivastava  (8 years ago)

distance travelled by front wheel = distance travelled by back wheel
let revolution be x+9 and x respectively
so 133(9+x)=190x
x=21
distance = 21(190) 0r 133(21+9) = 3990

Is this solution Helpfull? Yes (65) | No   

Ram Vyas  (8 years ago)

LCM of 133 and 190 is 1330

by this we can calculate
front wheel need 10 rounds to travel 1330 as 133*10 = 1330
back wheel need 7 rounds to travel 1330 as 190*7 = 1330

front wheel rounds 3more than back wheel in 1300uneve
10rounds of front wheel = 7round of back wheel

now given is front wheel has done 9 more revolutions
10*3 round of front wheel = 7*3 round of back wheel
30 round of front wheel = 21 round of back wheel

hence distance traveled by cart = 30 * 133(uneves in 1 round) = 3990 uneves

Is this solution Helpfull? Yes (14) | No (3)  

NEHA CHATTERJEE  (8 years ago)

Let x be the distance.
x/133=x/190 + 9
x/130-x/190=9
x=3990 uneves (c)

Is this solution Helpfull? Yes (5) | No (1)  

Smruthi M  (6 years ago)

Both the tyres belong to a cart

So the distance travelled by them will be same

Also front wheel which is smaller revolves 9 times more than rear wheel.

If rear wheel revolves 'x' times, then front wheel revolves 'x+9' times

A wheel covers k distance of its circumference is k

Hence,

Distance travelled by front wheel = 133*(x+9)
Distance travelled by rear wheel = 190*X

Equate it!
And we find 'x' to be 21

Hence, distance travelled by the cart is 190*21 or 133*(21+9)

That is, 3990

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sunl namdev  (8 years ago)

my ans is b 1330
becausce 133+133*9 =1330

Is this solution Helpfull? Yes | No (5)  

Sam Diego  (8 years ago)

Effective length traversed => 133(9+x)=190x
x=21
total length travelled=21*190.

Is this solution Helpfull? Yes | No (1)  

Aritra Chakraborty  (8 years ago)

in 1 full rotation of rear wheel the front wheel rotates = (190-133)/133 = 57/133 times & the car moves 190 uneves.. hence in 9 times the car will move = 190*133*9/57 = 3990 uneves.

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Arpit Motwani  (8 years ago)

c is the answer

Is this solution Helpfull? Yes | No (2)  

shagufta  (8 years ago)

LCM of 133 and 190= 1330
so front wheel takes 10 rounds and rear wheel takes 7 rounds

So for 3 rounds extra, 1330 uneves distance has to be travelled. To take 9 rounds extra, 1330 × 3 = 3990 uneves has to be traveled.

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