• Placement Papers
• /
• Elitmus
• /
• Numerical Ability
• /
• Log and Antilog

Elitmus Question Papers:

(#M40154116) ELITMUS Numerical Ability question apptitude Keep an EYE

if logN base3+logN base9,sum is whole number,then how many number possible for N between 100 to 100?
A)1
B)20
C)111
D)i didn't remember

Asked In Elitmus KIRAN (9 years ago)

Unsolved Read Solution (5)

Is this Puzzle helpful?   (10)   (3) Submit Your Solution Log and Antilog

Read Solution (5) :

Anjai Baghel  (9 years ago)

ans =1

N value should be in between 10 to 100

log 81 base 3 + log 81 base 9 is possible

Is this solution Helpfull? Yes (17) | No   

LAV KUMAR  (9 years ago)

answer should be option (A)
we can write logN base3=(logN baseX/log3 baseX);
and logN base9=(logN baseX/log9 baseX);
now, logN base3+logN base9= ( logN baseX / log3 baseX + logN baseX / log9 baseX)
=logN baseX (1/log3 baseX + 1/2log3 baseX) bcz (3 square =9)
=logN baseX ( 3log3 baseX / 2log3 baseX *log3 baseX) by simple addition
=logN base X ( 3/2log3 base X)
or =logN base X *3 / log9 base X
or =3 * logN base 9:
so N should be 81 because it is a 9 square and it also ies between 10 to 100.

Is this solution Helpfull? Yes (7) | No   

Akshay  (9 years ago)

answer should be 2
since log(9)+log(9)=3 for base 3 and 9 respectively
log 81+ log 81=6 for base 3 and 9 respectively

Is this solution Helpfull? Yes (4) | No (2)  

Roushan  (9 years ago)

ans=1 because 81 is only value between 10 to 100

Is this solution Helpfull? Yes (1) | No   

Abhishek  (9 years ago)

@akshay value must be in range {10 to 100 }

Is this solution Helpfull? Yes (1) | No (1)  

Please Login to Read Solution.