Latest Elitmus Aptitude Question SOLUTION: if 1/a + 1/b + 1/c = 1/(a+b+c) where a+b+c !=(not equals) 0, abc != 0 , then what is the value of X=(a+b) (b+c) (c+a)+(a+b+c)?

• Placement Papers
• /
• Elitmus
• /
• Numerical Ability
• /
• Age Problem

Elitmus Question Papers:

(#M40155180) ELITMUS Numerical Ability question no. system Keep an EYE

if 1/a + 1/b + 1/c = 1/(a+b+c) where a+b+c !=(not equals) 0, abc != 0 , then what is the value of X=(a+b) (b+c) (c+a)+(a+b+c)?

Asked In Elitmus as (8 years ago)

Unsolved Read Solution (11)

Is this Puzzle helpful?   (5)   (1) Submit Your Solution Age Problem

Read Solution (11) :

ANAMIKA KUMARI  (8 years ago)

x = a+b+c
because, (a+b)(b+c)(c+a) = 0

Is this solution Helpfull? Yes (9) | No   

Yamini Kant Mahato  (8 years ago)

Hii...REENA..Almost company hiring through overall marks cutoff.It depends on Company to company... Like Accenture hiring through overall score..It may be negative marking in any section..But finally you have score overall more than 100 marks as well as you have to also come under selected college list...And in word of CGI...This company will call if you have more than 50 Marks...!!!

Is this solution Helpfull? Yes (3) | No   

Yamini Kant Mahato  (8 years ago)

Crypto Was:
X D L
H A E
-----------
D E P H
3 P K P
__ A D __
------------
P __ __ K D H I AM UNABLE TO FLASH BACK THE EXACT 2 CHARACTERS SO I LEFT BLANK.BUT I AM GIVING THE EXACT SOLUTION OF THE ABOVE CRYPTO:

5 4 7
3 6 9
________
4 9 2 3
3 2 8 2
1 6 4 1
___________
2 0 1 8 4 3 SO SIMPLY YOU HAVE TO PUT THE VALUE OF 1 AND 0.I CAN'T CALL BACK THE VALUE OF 0
AND 1.
Q.1 WAS:D*H*E=4*3*9=108
Q.2 WAS:P*D*K=2*4*8= 64
Q.3 WAS:X*P*__=5*2*1= 10 THE VALUE OF 1 CAN'T CALL FRIENDS.

Is this solution Helpfull? Yes (3) | No   

rahul  (8 years ago)

0
(ab+bc+ca)/abc=1/(a+b+c)
=> abc=a2b+ab2+ac2+a2c+b2c+bc2+3abc
=> a2b+ab2+ac2+a2c+b2c+bc2+2abc=0

(a+b)(b+c)(c+a)=(ab+ac+b2+bc)(c+a)
=abc+ac2+b2c+bc2+a2c+a2b+b2a+abc
=0

Is this solution Helpfull? Yes (2) | No (4)  

ajit patel  (8 years ago)

1/a + 1/b = 1/(a+b+c) - 1/c

(a+b)/ab = c-a-b-c/ (a+b+c)*c /* cross multiply*/

After cancelling (a+b)

1/ab = -1/[ (a+b+c)*c]

Cross multiply

(a+b+c)*c = -ab
ac + bc + c^2 = -ab
ac + ab + bc + c^2 = 0
a(b+c) + c (b+c) = 0
(b+c) * (a+c) = 0
Hence value is 0

Is this solution Helpfull? Yes (2) | No   

Vikas Jha  (8 years ago)

Either >0 or

Is this solution Helpfull? Yes (1) | No   

Vikas Jha  (8 years ago)

a=-b will be the only case so (a+b)(b+c)(c+a) part will be zero. Hence it totally depends on the value of c. So either >0 or

Is this solution Helpfull? Yes (1) | No   

Reena  (8 years ago)

in elitmus i got
66% in verbal
87% in problem sloving
30% in quant ????is there any chance to get the call?????

Is this solution Helpfull? Yes | No (12)  

Harathi.Chappidi  (8 years ago)

hi friends i wrote elitmus exam in the last month i got very less score in quantum ability.How to prepare for it to get good score,pls help me

Is this solution Helpfull? Yes | No   

Jinal  (8 years ago)

ans is abc

Is this solution Helpfull? Yes | No   

Abhijeet Shaw  (8 years ago)

put a=1 b=2 c=3
answer is abc

Is this solution Helpfull? Yes | No (2)  

Please Login to Read Solution.