Latest Oracle Aptitude Question SOLUTION: If the length & width of a rectangle is decreased by 50% & then again increase the new length & width by 40%. Calculate the percentage difference between the area of New Rectangle

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If the length & width of a rectangle is decreased by 50% & then again increase the new length & width by 40%. Calculate the percentage difference between the area of New Rectangle & Original Rectangle.

Asked In Oracle ROHIT (8 years ago)

Solved Abhineet kumar Read Solution (13)

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Read Solution (13) :

Abhineet kumar  (8 years ago) Best Solution

51%r
let length is l, width is w so area is wl
after decreament l is i/2 ,w is w/2
again inc by 40% so l is 7l/10 ,w is 7w/10 so area is 49wl/100
percentage change is wl-49wl/100=51wl/100
so 51%

Is this solution Helpfull? Yes (11) | No (2)  

Satyarth Praveen  (8 years ago)

New rectangle is 51% smaller.

Is this solution Helpfull? Yes (2) | No (1)  

Ramgopal  (8 years ago)

take a number divisible by 4 and 5
let the side of the rectangle is 40x and 20y
now area is 800xy

width is decresed by 50%
now l=20x and w=10x
again incresed by 40%
again l=28x and w=14y
now area is 392xy

percentage change in area is ((800-392)/800)*100
51%

Is this solution Helpfull? Yes (2) | No   

Reshma  (8 years ago)

take the dimensions of original rectangle as 200*100 (l*b)
decreased by 50% = 100*50 this is the new dimensions
increase 40% in new dimensions i.e, 140*70 (40% of 100 is 40 so 100+40=140 and 40% of 50 is 20 so 50+20=70)
new area 140*70=9800
original area= 100*200=20000
difference in area=20000-9800=10200
% decrease= (10200*100)/20000=51%
Ans 51%

Is this solution Helpfull? Yes (1) | No   

Aindrila  (8 years ago)

51% smaller

original dimensions:
200x100
after 50% decrease:
100x50
after 40% increase:
140x70
So change in area:
(200*100)-(140*70)=10200
%change=(10200*100)/20000=51%

Is this solution Helpfull? Yes (1) | No (1)  

kanchan chaudhari  (7 years ago)

Decrease by 30%

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UMANG RASTOGI  (8 years ago)

80%
LET 1ST AREA=XY
2ND=XY+1/2XY
3RD=XY+1/2XY+1/5{2ND}
DIFF.=1ST-3RD;
=80%

Is this solution Helpfull? Yes | No (4)  

megha gupta  (8 years ago)

19 becayuse

Is this solution Helpfull? Yes | No (1)  

khushboo goenka  (8 years ago)

51 %
COZ NEW RWCTANGLE AREA=0.49 OD ORIGINAL RECTANGLE
HENCE DIFFERNCE IS 51

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jitu  (8 years ago)

8 * 3 - 3 / 8

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samaresh  (7 years ago)

the answer is 51%.let take length and bredth as x and y.then area is xy;now decrease 50% then area is xy/4;again increase area by 40% means area is 49xy/100.thus the result is 51%

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vimal tiwari  (7 years ago)

50% decreased : l/2 * b/2
40 % increased : 7l/10 * 7b/10

(original - new)/100 = (l*b - 7l/10* 7b/10 ) /100 = 51%

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uday  (7 years ago)

49% of the original area

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