Latest Capgemini Aptitude Question SOLUTION: 1- The sum of the ages of abhigail,jennifer and margaret was 52 three year ago.four years ago,jennifer who is a year younger than margaret,was 3/2 times as old as abhigail.the sum

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(#M40156068) CAPGEMINI Numerical Ability question Ages Keep an EYE

1- The sum of the ages of abhigail,jennifer and margaret was 52 three year ago.four years ago,jennifer who is a year younger than margaret,was 3/2 times as old as abhigail.the sum of ages of jennifer and margaret two year hence will be?
a- 51
b- 47
c-48
d-49
answer this.

Asked In Capgemini surya prakash (8 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

Pallavi Palak  (8 years ago)

3 yrs ago sum = A+j+m=52

present ages sum= A+j+m=61

J=M-1 or M =J+1

J-4 =3/2(A-4)

A= (2 J+4)/3

Substitute all in Second eqn of Sum of present ages

(2j+4)/3 + j + j +1 =61

8j =176
j=22 present , m= 23 present

after 2 yrs sum = (22+2) +(23+2) =49

Is this solution Helpfull? Yes (40) | No (6)  

SANKET SHARAD PAREKH  (8 years ago)

d 49

x+y+z = 52 before 3 yr ago
four yr ago x+y+z=49 ..............(1)
condition given is 3/2(z) + 3/2(z) + 1 + z =x+y+z= 49

by solving this z=12

x= 3/2(z) = 3/2 *(12) =18
y = x+1 =19
But this is for 4 yrs ago
So current ages are x=22 and y=23
after 2 yrs it will be x=24 and y=26
so x+y=49

Is this solution Helpfull? Yes (9) | No (7)  

JASPREET SINGH  (7 years ago)

49 is the ryt ans

Is this solution Helpfull? Yes (7) | No (2)  

ramya  (8 years ago)

b 47

x+y+z = 52 before 3 yr ago
after 3 yr each one age is increased by 3 hence now x+y+z=61
four yr ego x+y+z= 58 ..............(1)
condition given is 3/2(z) + 3/2(z) + 1 + z = x+y+z = 58

by solving this z=14

x= 3/2(z) = 3/2 *(14) =21
y = x+1 =22

x+y = 43 hence 2 yr each one age will increase by 2 so 43+4 == 47

Is this solution Helpfull? Yes (3) | No (16)  

kajal  (7 years ago)

ans is d=49

Is this solution Helpfull? Yes (3) | No   

abhinai  (8 years ago)

b) 47

A+J+M=52 ( 3 years ago)

At present Every one age vil b incresed 3, At now A+J+M= 61

4 Years ago A+J+M = 57

Acc. to condition----> A+(1.5 of A)+ (1.5 of A + 1) = 57
J = As jennifer is 3/2 times old as Abhigali
M= As Jennifer is a Year is Younger than margaret
M= ( 1.5 of A )+ 1

On Solving we Get A = 14 i.e, Abhigali
Jennifer is 1.5 of 14 = 21
Margaret is J+1 = 22

After 2 years---------> j+M = (21+2) + (22+2)
= 47

Is this solution Helpfull? Yes (2) | No (13)  

ramya  (8 years ago)

b 47

x+y+z = 52 before 3 yr ago
after 3 yr each one age is increased by 3 hence now x+y+z=61
four yr ego x+y+z= 58 ..............(1)
condition given is 3/2(z) + 3/2(z) + 1 + z = x+y+z = 58

by solving this z=14

x= 3/2(z) = 3/2 *(14) =21
y = x+1 =22

x+y = 43 hence 2 yr each one age will increase by 2 so 43+4 == 47

Is this solution Helpfull? Yes (1) | No (24)  

pooja  (4 years ago)

d.49 as m=19

Is this solution Helpfull? Yes | No   

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