Latest Elitmus Aptitude Question SOLUTION: Let A be a natural number consisting only 1. B is another natural number which is equal to quotient when A is divided by 13. C is yet another natural number equal to the quotient w

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(#M40156092) ELITMUS Numerical Ability question Keep an EYE

Let A be a natural number consisting only 1. B is another natural number which is equal to quotient when A is divided by 13. C is yet another natural number equal to the quotient when B is divided by 7. Find B-C.

Asked In Elitmus sahil aggarwal (8 years ago)

Unsolved Read Solution (5)

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jitendra kumar singh  (8 years ago)

a/c to question A contain only 1
let A=111111 when which is divide by 13 we get quotient 8547 and remainder=0 {111111 is 1st no. which is divisible by 13}.
this quotient is equal to i.e B=8547
and c equal to quotient of B when it is divided by 7
then we get C=1221
now B-C=8547-1221=7326. ans

Is this solution Helpfull? Yes (24) | No   

Sanjeet Jaiswal  (7 years ago)

In above problem reminder should be zero. Otherwise each one will get different answer. Also A should be least possible number (that is not mentioned in question, this should be understood).

111111/13=8547=B
8547/7=1221=C

B-C=7326

Is this solution Helpfull? Yes (6) | No   

mohit  (8 years ago)

a=111,b=8, c=1
ans 7

Is this solution Helpfull? Yes (2) | No (6)  

Ram Krishna  (8 years ago)

To proof: x^2=a*8(multiple of 8)

checking i). x^3=b*16
take cube root and then square both sides
x^2=2^(8/3) * b^(2/3)
which is not a multiple of 8 certainly.

checking ii). x=c*18=2*3^2*c
square both sides
x^2=4*3^4*c^2
which is not always a multiple of 8 .for it c should be even.
taking both
x^3/x= x^2=8*(b/9c)=8*k

BOTH statements (1) and (2)
TOGETHER are sufficient to
answer the question asked,
but NEITHER statement
ALONE is sufficient to answer
the question asked

Is this solution Helpfull? Yes | No (7)  

Rajat kamra  (8 years ago)

B-C would be = 6
here a= 11, b=1,c=7

Is this solution Helpfull? Yes | No (4)  

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