Latest Elitmus Aptitude Question SOLUTION: how may number are there greater than 6*10^6 by using digits 5,6,9,0 . repetition is not allowed? a-180 b-520 c- not remember

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(#M40157327) ELITMUS Numerical Ability question Keep an EYE

how may number are there greater than 6*10^6 by using digits 5,6,9,0 . repetition is not allowed?
a-180
b-520
c- not remember

Asked In Elitmus amit maurya (8 years ago)

Solved Saurabh Rathour Read Solution (14)

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Read Solution (14) :

Saurabh Rathour  (8 years ago)

question is wrong ,
Correct question is that asked in elitmus ..
how may number are there greater than 6*10^6 by using digits 5,5,6,6,9,9,0 when repetition is not allowed?

Is this solution Helpfull? Yes (34) | No (5)  

krishna  (8 years ago)

7 places - _ _ _ _ _ _ _
using permutations rule
1st place - (6,6,9,9) - 4!
similarly,
in order of places- 4 6 5 4 3 2 1
now, since (2,6,9) have commons -
(4*6*5*4*3*2*1)/(2!*2!*2!) = 360

Is this solution Helpfull? Yes (33) | No (7)  

Mallikarjuna Reddy  (8 years ago)

Numbers should be greater than 6*10^6

It means numbers should start with 6 and 9(from the given digits only this two)

Starting with 6
6 _ _ _ _ _ _
above 5 places can be filled with remaining 6 digits in 6!/(2!*2!) =>180

Starting with 9
9 _ _ _ _ _ _
above 5 places can be filled with remaining 6 digits in 6!/(2!*2!) =>180

Total =180+180 =360

Is this solution Helpfull? Yes (30) | No (4)  

Saurabh Rathour  (8 years ago) Best Solution

and its answer is 360.
(4*6!)+(2!*2!*2!*2!)

Is this solution Helpfull? Yes (9) | No (20)  

praveen kumar reddy  (8 years ago)

360..iam i right!

Is this solution Helpfull? Yes (2) | No (7)  

RAJ  (8 years ago)

since there are 7 places and the no has to be greater than 6*10^6
and the no are 5,5,6,6,9,9,0
_ _ _ _ _ _ _=2*6*5*4*3*2*1=180

Is this solution Helpfull? Yes (2) | No (3)  

Shikhar Agarwal  (8 years ago)

this is not possible as it has to bea seven digit no and not possible with 4 digits

Is this solution Helpfull? Yes (1) | No (8)  

lohit  (8 years ago)

7 places - _ _ _ _ _ _ _
1st place - (6 or 9) = 2
similarly,
second place there is (5,6,9,0) = 4
same as other places

2*4*4*4*4*4*4 = 8192 answer

i think some part of question is missing that is why answer is not in options

Is this solution Helpfull? Yes (1) | No (6)  

sooraj singh  (7 years ago)

@saurabh rathour can u explain the approach plz ?

Is this solution Helpfull? Yes (1) | No (1)  

dxd  (7 years ago)

bakwas site hai , genuine question ko change karke puchha gaya hai, please don.t use this site anymore

Is this solution Helpfull? Yes (1) | No (3)  

Sudharani Irala  (8 years ago)

520 bt how i dnt know

Is this solution Helpfull? Yes | No (10)  

shehzad  (8 years ago)

since 7 digits are given in the question so any seven digit number formed from the combination of these digits (except the ones starting from zero ) would be greater than 6*10^6.
so the correct method is total of seven digits no. + six digits no. (starting from 0) greater than 6*10^6
i.e. (6*6!)/(2!*2!*2!) + (4*5!)/(2!*2!*2!*)

Is this solution Helpfull? Yes | No   

sivagurunathan  (7 years ago)

use this formula n!/(n-r)! n:6 r:4 have fun

Is this solution Helpfull? Yes | No (2)  

divanshu  (7 years ago)

In the question it is given that digits should not be repeted. So how can we use Two five's,two nine's.?

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