Latest cocubes Aptitude Question SOLUTION: solve this :- 3,10,21,?,65,133

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(#M40157484) COCUBES Logical Reasoning question Keep an EYE

solve this :-
3,10,21,?,65,133

Asked In cocubes b chaudhary (7 years ago)

Unsolved Read Solution (19)

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Read Solution (19) :

Abhishek  (7 years ago)

3,10,21,?,65,102,133
n x (next prime no.)
1 x 3 = 3;
2 x 5 = 10;
3 x 7 = 21;
4 x 11 = 44;
5 x 13 = 65;
6 x 17 = 102;
7 x 19 = 133;

Is this solution Helpfull? Yes (58) | No (12)  

umesh kumar yadav  (7 years ago)

Answer is 38.
2^1+1=3
2^2+6=10
2^3+13=21
2^4+22=38
2^5+33=65
And so on.

Is this solution Helpfull? Yes (13) | No (57)  

sharad bhosale  (7 years ago)

why you added 1,6,13,22 and 33.?

Is this solution Helpfull? Yes (8) | No (7)  

ananya das  (7 years ago)

what about 133?
according to umesh's logic
2^6+69=133..
how 69 comes in the series 1,6,13,22,33..??????

Is this solution Helpfull? Yes (6) | No   

mohd sahil khan  (7 years ago)

44
odd prime number are there in series 3*1=3,5*2=10,7*3=21so 11*4=44

Is this solution Helpfull? Yes (3) | No   

alpha corleone  (7 years ago)

21 is answer
as 3*6+3=21
10*6+5=65
21*6+7=133

Is this solution Helpfull? Yes (2) | No (16)  

shubham kumar  (7 years ago)

answer is 38
2^1+1=3
2^2+6=10
2^3+13=21
2^4+22=38

Is this solution Helpfull? Yes (2) | No (2)  

Pratyusha   (7 years ago)

44, 1*3=3,2*5=10,3*7=21,4*11=44,5*13=65,6*17=102,7*19=133

Is this solution Helpfull? Yes (2) | No   

Tharaheswari  (7 years ago)

44
Because it contain odd numbers multiply by the numberic numbers

Is this solution Helpfull? Yes (2) | No   

Idemakanti Madhuri  (7 years ago)

44.............multiplication of numbers with their next prime numbers
i.e, 1*3=3
2*5=10
3*7=21
4*11=44
5*13=65
6*17=102

Is this solution Helpfull? Yes (2) | No   

Satyaki Ghosh  (6 years ago)

The formula
n(2n+1)
or
n^2+n^2+n
1^2+1^2+1
2^2+2^2+2
3^3+3^3+3

Is this solution Helpfull? Yes (2) | No   

Hemanth  (7 years ago)

i agree with the answer that Mr.Umesh has given and also i would like to give my explanation for the answer
as you can see they are all in the increasing orders of 2^x apart from that you cans see the numbers that are added up to the 2^x the differences between the two consecutive numbers are as follow 5,7,9,11 which are odd number series

Is this solution Helpfull? Yes | No (3)  

OWAIS  (7 years ago)

The total sum is equal to the sum of AP and GP.
Sum of AP gives : n/2(2a+(n-1)d)= 216
since a=20,d=2 and n=8;
for gp sum is a(r^n-1)/r-1=3279
since a=3 and n=7,r=3;
hence total is 3279+216=3495

Is this solution Helpfull? Yes | No (2)  

prasanna  (7 years ago)

3+3+1=10
10+10+1=21
21+21+2=44
65+65+3=133

Is this solution Helpfull? Yes | No (8)  

lucky  (7 years ago)

3,10,21,36,55,65,133

Is this solution Helpfull? Yes | No (1)  

P saikiran reddy  (6 years ago)

The numbers represent the odd prime numbers.
So,

3 * 1 = 3
5 * 2 = 10
7 * 3 = 21
11 * 4 = 44
13 * 5 = 65
17 * 6 = 102
19 * 7 = 133.

So, the missing term is 44.
And, the series is 3, 10, 21, 44, 65,133

Is this solution Helpfull? Yes | No   

Dhanush  (5 years ago)

3,10,21,?,65,102,133
1 x 3 = 3;
2 x 5 = 10;
3 x 7 = 21;
4 x 11 = 44;
5 x 13 = 65;
6 x 17 = 102;
7 x 19 = 133;

Is this solution Helpfull? Yes | No   

Prerna Midha  (5 years ago)

44
1*3=3
2*5=10
3*7=21
4*11=44
5*13=65

Is this solution Helpfull? Yes | No   

mallesettu pranitha  (5 years ago)

11*4 =44
44 is answer

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