Latest TCS Aptitude Question SOLUTION: find the greatest number that will divide 148 246 and 623 leaving remainders 4 6 and 11 respectively

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(#M40157536) TCS Numerical Ability question Keep an EYE

find the greatest number that will divide 148 246 and 623 leaving remainders 4 6 and 11 respectively

Asked In TCS keerthna (7 years ago)

Unsolved Read Solution (10)

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Read Solution (10) :

Padmaja   (7 years ago)

Hcf ( (148-4), (246-6), (623-11))=12

Is this solution Helpfull? Yes (9) | No (5)  

M.Gayatri Prathyusha  (7 years ago)

148-4=144
246-6=240
623-11=612
Hence these 3 are divided by 12 leaving remainders 4 6 and 11

Is this solution Helpfull? Yes (6) | No   

Nagendra Balam  (7 years ago)

hcf of 144, 240,612 is 12. 12 is the answer

Is this solution Helpfull? Yes (2) | No (1)  

Aditya srinivas  (7 years ago)

difference of the dividend and remainder gives you the divisible number
so Hcf of ((148-4),(246-6),(623-11)
144=12*12
240=12*20
623=12*51
so the HCF is 12.

Is this solution Helpfull? Yes (2) | No   

teja  (7 years ago)

hcf of given numbers is 12

Is this solution Helpfull? Yes | No   

Swati kumari  (6 years ago)

a*4/100=8 , a=800/4, a=200
b*8/100 , b=400/8, b=50
c=50/200, c=1/4

Is this solution Helpfull? Yes | No (2)  

RM ARUNACHALAM  (4 years ago)

148-4=144
246-6=240
623-11=612
Hence these 3 are divided by 12 leaving remainders 4 6 and 11

Is this solution Helpfull? Yes | No   

NITISH KUMAR  (4 years ago)

Ans2
148-4=144
246-6=240
623-11=612
144-= 2*2*18
240= 2*2*3*20
612=2*2*
2 great no

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sakshi tripathi  (4 years ago)

We know that When a greatest number that divide x,y,z and leaves remainder a,b,c respectively = HCF of (x - a),(y - b),(z - c).

Now,

HCF of (148 - 4),(246 - 6),(623 - 11)

= > HCF of (144, 240,612)


Prime factorization of 144 = 2 * 2 * 2 * 2 * 3 * 3

Prime factorization of 240 = 2 * 2 * 2 * 2 * 3 * 5

Prime factorization of 612 = 2 * 2 * 3 * 3 * 17

HCF(144,240,612) = 2 * 3 * 3 = 12.


Hence, the greatest number is n = 12.


Now,

We have to find the remainder when n is divided by 7.


= > 7)12(1

        7

       ---

        5.

Therefore, the remainder is 5.

Is this solution Helpfull? Yes | No   

Dipali Bhausaheb Gorane  (4 years ago)

148-4=144,246-6=240,623-11=612
HCF of 144,240,612 is 12.

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