Latest Accenture Aptitude Question SOLUTION: (x^n -27) is divisible by: (x-3), when n =? OPTIONS: ANS:1,2,3,4

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(x^n -27) is divisible by: (x-3), when n =?
OPTIONS: ANS:1,2,3,4

Asked In Accenture saidinesh (7 years ago)

Solved savera kumari Read Solution (5)

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savera kumari  (7 years ago) Best Solution

answer will be 3...
go with the options... (x^1 -27) not divisible by (x-3)
when we put the the value of n as 3, (x^3 - 27)/(x-3)
(x^3 - 3^3)/(x-3) as we know the formula of (a^3 -b^3) is (a-b)(a^2+ab+b^2) same way put the formula (x-3)(x^2+3x+3^2)/(x-3) so 3 will be the answer

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SUDEEP GHOSH  (7 years ago)

ans 3.
because x to the power 3 and 3 to the power 3 means 27..

Is this solution Helpfull? Yes (3) | No (2)  

srisaranya  (6 years ago)

option:3
(calculate the power as three)

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Divya Batra  (6 years ago)

n=3
-By using identity formula of cubes i.e. a^3-b^3=(a-b)*(a^2+a*b+b^2)
therefore, (x^3-27)/(x-3) can be expanded as
=(x^3-3^3)/(x-3)
=((x-3)*(x^2+3*x+3^2))/(x-3)

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  (5 years ago)

(x^3-3^3)%(x-3)=0

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