Latest Elitmus Aptitude Question SOLUTION: pandavas Yudisthir Arjun Bhim Nakul Sahdev participate in a wrestling tournament. Shakracharya decide one man will play 2 games at home and 2 games away. They play only once to eac

First tings first. As per question there will be 10 games total. now as no body wins equal games,
this means that 10 = sum of 5 non equal number . this can be only satisfied by
10 = 0+1+2+3+4

Therefore the 5 people have won followig number of games

0
1
2 ---- Yudhishtar (given in question)
3
4

now as only 3 away games have been won as away, this means they must be won by the player winning 3 and 4 games. as otherwise it is not possible to win 3 or 4 games as 2 games are home game and 2 are away for each player

From this we can conclude that yudhishtar must have won both home games and lost both away games.Following are the 10 combinations that we can draw for these matches (g indicates it is given in question). Also note as yudhistar lost both his away games , then nakul and sehdev must have won atleast 1 game and therefore it can only be either bhim or arjun who wins 0 games.

away ----- home winner
----------------------
bhim Yudhi -g Yudhishtar
bhim arjun -g
arjun Yudhi -g Yudhistar
Sahdev nakul -g
Sahdev bhim
Nakul bhim
arjun sahdev
yudhi sahdev sahdev
nakul arjun
Yudhi nakul nakul


Now when you try with bhim winning 0 games you will get


away ----- home winner(as per data) winner if bhim wins 0
----------------------

bhim Yudhi -g Yudhishtar
bhim arjun -g 1-Arjun ( as bhim wins 0 arjun must win)
arjun Yudhi -g Yudhistar
Sahdev nakul -g 6- as 3 games away have already be won this must be a home win
Sahdev bhim 3-sah (as bhim wins 0 sahdev must win this)
Nakul bhim 2- nakul (as bhim wins 0 nakul must win this)
arjun sahdev 5-sah( based on 4 point arjun is suppose to win 1 game only)
yudhi sahdev sahdev
nakul arjun 4- nakul (as nakul and shedev have won 2 games they must be the ones winning 3 and 4 games because yudhishar is the one winning 2 games )
Yudhi nakul nakul


When you try the same with arjun winning 0 games it is not solvable so the winning counts are


0- bhim
1-Arjun
2-Yudhishtar
3-Sahdev
4-Nakul

1; Bhim
2: 4-2=2
3: yudhisthir 0 games

I think
Maxm game win by Bheem.

please explain

I think the question is not clarity.

somebody explain this puzzle pls

please explain the question because question seems to be wrong.