Latest Elitmus Aptitude Question SOLUTION: A rectangle is inscribed in circle of area pi/2 with radius r,then what is perimeter of rectangle 1)2r 2)8r 3)2sqrt(2)r 4)4sqrt(2)r

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(#M40164380) ELITMUS Numerical Ability question geometry Keep an EYE

A rectangle is inscribed in circle of area pi/2 with radius r,then what is perimeter of rectangle
1)2r
2)8r
3)2sqrt(2)r
4)4sqrt(2)r

Asked In Elitmus Siva nagendra (7 years ago)

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Read Solution (1) :

Amit kumar  (7 years ago)

Area = pi*r*r=pi/2 (given)
on solving we get;
r=1/root2

Now the diagonal of the rectangle will be double the radius ,since the radius of circle will act as the mid point of any diagonal.
So diagonal= 2* (1/root 2) = root 2
Now using pythagoras theorem we have;
hypotenuse = root 2
so length of sides will be 1.
so perimeter = 2 (1+1)= 4
= 2sqrt(2)r= 2*root 2 * (1/ root 2) = 4

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