Latest Elitmus Aptitude Question SOLUTION: x lies from 121 < x >1331, x^2+1 when divided by 11 what will not be the remainder . A.1 b.4 c.6 d.8

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(#M40164382) ELITMUS Numerical Ability question Elitmus 16/4/17 Keep an EYE

x lies from 121 < x >1331, x^2+1 when divided by 11 what will not be the remainder .
A.1 b.4 c.6 d.8

Asked In Elitmus Deepak Bharty (7 years ago)

Unsolved Read Solution (4)

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vikash  (7 years ago)

since x should be greater than 121, let us suppose that 'y' is no. which is greater than 0,
now we can write, x^2+1 as (121+y)^2 +1.
(y^2 + 121^2 + 2*121*y + 1)/11
y^2/11 + 121^2/11 + 2*121*y/11 + 1/11
y^2/11 + 0 + 0 + 1 ( remainder)
y^2/11 + 1
y^2 can be 1,4,9,16,25......
after dividing by 11,remainder we got 1,4,6 but not 8.
so ans is d.

Is this solution Helpfull? Yes (19) | No (6)  

sai  (7 years ago)

Vikash Please clarify

since x should be greater than 121, let us suppose that 'y' is no. which is greater than 0,
now we can write, x^2+1 as (121+y)^2 +1.
(y^2 + 121^2 + 2*121*y + 1)/11
y^2/11 + 121^2/11 + 2*121*y/11 + 1/11
y^2/11 + 0 + 0 + 1 ( remainder)
y^2/11 + 1
y^2 can be 1,4,9,16,25......
after dividing by 11,remainder we got 1,4,6(is it 6 or 9),5.... and we should add +1 also to this right because of 1/11 ??

Is this solution Helpfull? Yes (5) | No (1)  

ratul  (7 years ago)

option d>8

Is this solution Helpfull? Yes (1) | No   

nashrah  (7 years ago)

how u got ths

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