Latest Wipro Aptitude Question SOLUTION: 1*2*3*4*5 11*12*13*14*15 21*22*23*24*25 16*17*18*19*20 6*7*8*9*10

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(#M40165011) WIPRO Programming question pattern Keep an EYE

1*2*3*4*5
11*12*13*14*15
21*22*23*24*25
16*17*18*19*20
6*7*8*9*10

Asked In Wipro Shubham singhal (6 years ago)

Unsolved Read Solution (31)

Is this Puzzle helpful?   (182)   (70) Submit Your Solution Program

Read Solution (31) :

  (5 years ago)

public class Main {

public static void main(String[] args) {
// write your code here
int row,col,lim,nl,ev,od,a;
lim=25;
nl=5;
a=0;

od= (lim/nl)/2;
ev= (lim/nl) - od;

//Printing the first row to the middle row

for(row=0;row

Is this solution Helpfull? Yes (61) | No (27)  

  (6 years ago)

#include
void main()
{
int n=25;
int a[25],i,j,k,count1,count2;
for(i=0;i

Is this solution Helpfull? Yes (24) | No (34)  

Lakshman  (5 years ago)

import java.util.*;

public class Main
{
public static void main(String[] args)
{
int n=0,c=1,e=0;
Scanner scan = new Scanner(System.in);
System.out.println("enter the no of rows(should be odd no.)");
n=scan.nextInt();
for(int i=1;i

Is this solution Helpfull? Yes (17) | No (10)  

Avinandan SenGupta  (5 years ago)

#include
int main()
{
int row;
printf("Enter rows of pattern to printn");
scanf("%d",&row);
int arr[20][20];
int count=1;int lb=0;int ub=row-1;
while(count!=(row*row))
{

int point=lb;
for(int i=0;irow*row)
break;
point=ub;
for(int i=0;i

Is this solution Helpfull? Yes (14) | No (16)  

  (5 years ago)

class Wipro{
public static void main(String[] abc) {
int arr[][]= {{1,2,3,4,5},{6,7,8,9,10},{11,12,13,14,15},{16,17,18,19,20},{21,22,23,24,25}};
int a=2;
int b=4;
int c=1;
for(int i=0;i

Is this solution Helpfull? Yes (7) | No (9)  

  (5 years ago)

#include
void main()
{
int n,i,j,k;
printf("number");
scanf("%d",&n);
for(i =0;i

Is this solution Helpfull? Yes (5) | No   

Manuja.d.r  (6 years ago)

26*27*28*29*30

Is this solution Helpfull? Yes (4) | No (8)  

Sainath Pawar  (5 years ago)

import java.util.Arrays;

public class RandomExample {




public static void main(String[] args) {
int [][] a = new int[5][5];

int resetValueOfi=0;
int countNum=1;
int keepCount=0;
int rowJump=2;

outer:

for(int i=resetValueOfi;i

Is this solution Helpfull? Yes (3) | No (5)  

mrityunjay  (5 years ago)

//python

n = int(input())
for i in range(3):
for j in range(1,n+1):
if j != n:
print(n*2*i + j ,end = "*");
else:
print(n*2*i + j ,end = "");
print()
for i in range(2,0,-1):
for j in range(1,n+1):
if j !=n:
print(n*(2*i-1) + j , end = "*")
else:
print(n*(2*i-1) + j , end = "")

print()

Is this solution Helpfull? Yes (3) | No   

Vaishnavi.S  (5 years ago)

Can anyone please send me this code to my email id-svaishnavihpt@gmail.com

Is this solution Helpfull? Yes (1) | No (3)  

shriyanka  (5 years ago)

#include
int main()
{
int i,j,k,a=0,j1,p;
for(i=1;i

Is this solution Helpfull? Yes (1) | No (4)  

Rajure Pragati Baliram  (4 years ago)

#include
using namespace std;
int main()
{
int n;
coutn;
int p=n;
if(n>=1 && n

Is this solution Helpfull? Yes (1) | No   

Nidhi d  (5 years ago)

Can anyone please send me the previous placement paper of work to nidhidubeyjk@gmail.com

Is this solution Helpfull? Yes | No (4)  

Punit Pratim  (5 years ago)

#include

main(){
int i,j;
for(i=0; i

Is this solution Helpfull? Yes | No (4)  

RAJU SIVASANKAR  (5 years ago)

import java.io.*;
class Pattern
{
public static void main(String[] args)
{
int i;
int N=5;
for(i=0; i0; i-=2)
System.out.printf("%d*%d*%d*%dn", (4*i+1), (4*i+2), (4*i+3), (4*i+4));
}
}

Is this solution Helpfull? Yes | No (7)  

  (5 years ago)

#include
#define n 5
int main(void) {
int i,j,count,k,sum;
for(i=0;i

Is this solution Helpfull? Yes | No (2)  

anand mohan  (5 years ago)

#include

using namespace std;

int main()
{
int i,j,k=1;
for(i=1;i

Is this solution Helpfull? Yes | No (3)  

  (5 years ago)

class pattern
{
public static void main(String[]args)
{
int i;
for(i=1;i

Is this solution Helpfull? Yes | No (2)  

Subhadip Saha  (5 years ago)

#include
using namespace std;
int main()
{
int n;
coutn;
int p=n;
if(n>=1 && n

Is this solution Helpfull? Yes | No   

rajkumar.r  (5 years ago)

26*27*28*29*30
the continuous number can be multiple then it can be split in half of them

Is this solution Helpfull? Yes | No   

  (5 years ago)

#include

int main()
{
int x=0,y,i,d=6,j;
for(i=0;i

Is this solution Helpfull? Yes | No (1)  

vikas soam  (5 years ago)

import java.util.*;
import java.util.Scanner;
public class patternWipro
{
public static void main(String abc[])
{
Scanner sc=new Scanner(System.in);
System.out.println("Enter the size of row:");
int n=sc.nextInt();
int x=1,y=(n*(n*2)-(n-1));
for(int i=1;i

Is this solution Helpfull? Yes | No (1)  

akul rajput  (5 years ago)

for i in range(1,26):
print(i,end="")
if(i%5==0):
print("n")
else:
print("*",end="")

Is this solution Helpfull? Yes | No   

abhi  (5 years ago)

import java.util.*;
public class pattern {
public static void main(String [] args) {
Scanner scan=new Scanner(System.in);
System.out.println("Enter a number");
int n=scan.nextInt();
printPatt(n);
}
public static void printPatt(int n) {
int c=0;
for(int i=0;i

Is this solution Helpfull? Yes | No (2)  

Nilesh Mishra  (5 years ago)

import java.util.Scanner;

public class Main{

public static void main(String[] args) {
Main testClass = new Main();

int n;
System.out.println("Enter the value of N :");
Scanner in = new Scanner(System.in);
n = in.nextInt();
System.out.println("N : "+n);

testClass.printPattern(n);
}

private void printPattern(int num) {

int row=1,i=1,count =1;

String s ="";

//while( (row>0) | (count0)|(num>=count);) {

if(count=count);) {

if(count

Is this solution Helpfull? Yes | No   

  (4 years ago)

public static void printPattern(int n)
{

// Write your code here
int p=n;
if(n>=1 && n

Is this solution Helpfull? Yes | No   

  (4 years ago)

for(i=0;i

Is this solution Helpfull? Yes | No   

Sagar  (4 years ago)

n = int(input())

for i in range(n):

if(2*i < n):
k = n *(2*i)+1
j = 1
while(j

Is this solution Helpfull? Yes | No   

  (4 years ago)

//python

n=int(input())
for i in range(n):
if(i%2 == 0):
for j in range(n*i+1,n*i+1+n):
print(j, end =" ")
print()
for i in range(n-1,0,-1):
if(i%2 != 0):
for j in range(n*i+1,n*i+1+n):
print(j, end =" ")
print()

Is this solution Helpfull? Yes | No   

sds  (3 years ago)

i dont know the bloody answer

Is this solution Helpfull? Yes | No   

Gulfam  (1 year ago)

12345
1112131415
2122232425
1617181920
678910
that is
12345 for top then 678910
and then forward of 10 upto 5 no ahead
and follow above pattern

Is this solution Helpfull? Yes | No   

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