Latest Maths Aptitude Question SOLUTION: If m=(2-√3),then the value of (m6+m4+m2+1) /m3 is:

• Placement Papers
• /
• Maths
• /
• Numerical Ability
• /
• Age Problem

Maths Question Papers:

(#M40165282) MATHS Numerical Ability question Keep an EYE

If m=(2-√3),then the value of (m6+m4+m2+1) /m3 is:

Asked In Maths Partha pratim pratihar (6 years ago)

Unsolved Read Solution (1)

Is this Puzzle helpful?   (9)   (7) Submit Your Solution Age Problem

Read Solution (1) :

dhiraj prasad  (4 years ago)

given, (m⁶ + m⁴ + m² + 1)/m³
(m⁶/m³ + m⁴/m³ + m²/m³ + 1/m³)
(m³ + m + 1/m + 1/m³)
now,
m = (2 - √3)------------( 1 )
m³ = (8 - 3√3 - 6√3(2 - √3)
m³ = (8 - 3√3 - 12√3 + 18)
m³ = (26 - 15√3)-----------( 2 )
1/m = 1/(2 - √3) * (2 + √3)/(2 + √3)
1/m = (2 + √3)/(4 - 3)
1/m = (2 + √3)------------( 3 )
1/m³ = 1/(26 - 15√3) * (26 + 15√3)/(26 + 15√3)
1/m³ = (26 + 15√3)/(676 - 675)
1/m³ = (26 + 15√3)-------------( 4 )
adding------( 1 ) , --------( 2 ) , --------( 3 ) & --------( 4 )
(m + 1/m + m³ + 1/m³)
= (2 - √3 + 2 + √3 + 26 - 15√3 + 26 + 15√3)
= (4 + 52)
= 56
Hence, (m⁶ + m⁴ + m² + 1)/m³ = 56

Is this solution Helpfull? Yes (1) | No   

Please Login to Read Solution.